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How to automatically send a mail alert if the script errors out

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# 1  
Question How to automatically send a mail alert if the script errors out

I have a script like this, which calls other scripts from that script:



cat $readfile | while read line


file= `echo $line|awk '{print $4}'`

if [ $file ];
       then mv $file /home/temp_stage


I have to write the above script in such a manner that if it errors out any point, It has to automatically send an email notification. How do i find out if the file has errored out at any point.
I am struck at the point of... how to find if there is any error in the scripts that it calls...

Ur help is greatly appreciated.
Thanks in advance!

Last edited by Scott; 12-29-2009 at 12:02 PM.. Reason: Code tags, please!
# 2  
try something like this:
   echo "This script had an error on line $1" | /usr/bin/mailx -s 'script error'
   exit 1
}  || email_t $LINENO || email_t $LINENO

cat $readfile | while read line
  file= `echo $line|awk '{print $4}'`

  if [ $file ];
        mv $file /home/temp_stage

This assumes the other scripts return non-zero (i.e., exit 1) on error.
This User Gave Thanks to jim mcnamara For This Post:
# 3  
Thanks Jim.

Let me try with that.
Can u please explain to me, what does this "||" stand for in unix and hoe does it work?
I have never used it before.
# 4  
The "||" means only run what is after the "||" if the code before the "||" fails, the opposite is "&&" which means only run what is after the "&&" if the code before the "&&" has succeeded, e.g.:
cp fred /var && rm fred

Only delete fred if it was successfully copied to /var.
This User Gave Thanks to TonyFullerMalv For This Post:
# 5  
Thanks Tony!

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