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Passing array to functions in ksh script

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# 1  
Old 12-22-2009
Passing array to functions in ksh script
Let me know if there is a way to pass array to a funtion in ksh script.


Code:
function isPresent
{
  typeset member
  member=$1
  dbList=$2
  echo '$1:' $1
  echo '$2' $dbList



The array will be at the second position....something like this

Code:
isPresent 12 <array>
if [ $? -ne 0 ]
then
  echo "12 not present":
else
  echo "12 present";
fi

Last edited by pludi; 12-22-2009 at 02:57 AM.. Reason: code tags, please...
# 2  
Old 12-22-2009
Code:
## In this example the array contents are passed as a whole

function isPresent
{ 
	[[ ${2} == *${1}* ]] && return 0 
	return 1
} 

set -A n "ABC 12 DEF" 

isPresent 12 "${n[*]}" 

if [[ $? -ne 0 ]]
then 
	echo "12 not present"
else 
	echo "12 present"
fi

Code:
## In this example the array is accessed directly as the function can see the array

function isPresent
{ 
	[[ ${n[*]} == *${1}* ]] && return 0 
	return 1
} 

set -A n "ABC 12 DEF" 

isPresent 13 

if [[ $? -ne 0 ]]
then 
	echo "12 not present"
else 
	echo "12 present"
fi

# 3  
Old 12-22-2009
You could use a nameref (ksh93):

Code:
#!/bin/ksh
function isPresent
{
  typeset member=$1
  nameref dbList=$2
  [[ ${dbList[member]} != "" ]]
}

letterarray=(a b c d e f g h i j k l m n o p q r s t u v w x y z)

if isPresent 12 letterarray
then
  echo "12 is present"
else
  echo "12 is not present"
fi

Output:
Code:
12 is present

# 4  
Old 12-23-2009

In bash or ksh93:

Code:
array()
{
  eval "array=( \"\${${1}[@]}\" )"

  printf "%s\n" "${array[@]}"
}

q=( a b c d e f g )

array q

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