Shell Programming and Scripting

Hello all,
I want to list the file contents of the directory and number them. I am using la and awk to do it now,

#ls |awk '{print NR "." $1}'
1. alpha
2. beta
3. gamma

The problem I have is that some files might also have some spaces in the filenames.

#ls
alpha beta gamma some file with spaces.txt

Now I want it this way
1. alpha
2. beta
3. gamma
4. some file with spaces.txt

How do I do it?

Code:

printf '%s\n' *|nl

If the format is important:

Code:

printf '%s\n' *|nl -w1 -s.

I need something like this

Filename 1 is alpha
Filename 2 is beta
Filename 3 is gamma
Filename 4 is some file with spaces.txt

Code:

awk 'BEGIN {
  while (++i < ARGC)
    printf "Filename %d is %s\n", i, ARGV[i]
    }' *

Lets say, I have 3 files in a directory

#ls
alpha
beta
file with spaces

Now I want to list them in the following manner
<LI><A href="alpha">alpha</A>
<LI><A href="beta">beta</A>
<LI><A href="file with spaces">file with spaces</A>

I tried this,
ls |awk '{ print "<LI><A href=\" "$1" \"> " $1 "</A>"}'

It works fine for the files without spaces but only pickes up the first word of the file with spaces.

I know that I am doing it wrong, but am not sure of the corrected method. Please help.

Code:

ls |awk '{ print "<LI><A href=\" "$0" \"> " $0 "</A>"}'

I would avoid to use external commands (ls) in this case,
AWK can do it all .

Code:

awk 'BEGIN {
  while (++i < ARGC)
    printf "<LI><A href=\"%s\">%s</A>\n", ARGV[i], ARGV[i]
    }' *