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Convertion of Date Format using SQL query in a shell script

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# 1  
Old 11-19-2009
Question Convertion of Date Format using SQL query in a shell script
When I write

Code:
Select date_field from TableA fetch first row only

I am getting the output as 09/25/2009.

I want to get the output in the below format

2009-09-25 i.e., MM-DD-YYYY. Please help
# 2  
Old 11-19-2009
Hi.

Use to_char to get the format you want.

Code:
to_char( date_field, 'YYYY-MM-DD' )

http://www.techonthenet.com/oracle/f...ns/to_char.php
# 3  
Old 11-19-2009
I am getting the error as "SQL0440N No authorized routine named "TO_CHAR" of type "FUNCTION" having
compatible arguments was found. SQLSTATE=42884
"

Please help
# 4  
Old 11-19-2009
The TO_CHAR function is perhaps specific to ORACLE.
You haven't specify wich database you are using.

Jean-Pierre.
# 5  
Old 11-19-2009
Thanks for the response.I am using DB2 Database. Please help with the command for the same
# 6  
Old 11-19-2009
Try :
Code:
Select CHAR(date_field, ISO)  from TableA fetch first row only

The date is displayed with the format YYYY-MM-DD

Jean-Pierre.
# 7  
Old 11-19-2009
Hi aigles..
Thanks a lot!! it is working..May I know what is "ISO" ?
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