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awk command not working

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# 1  
Old 11-17-2009
awk command not working
Hi all,

Trying to write a script that reads a file and prints everything after a certain string is found to the end of the file. Awk is giving me an error and not sure why it doesn't work:

Code:
 
# cat test_file
Mon Nov 16 2009 16:11:08
abc
def
Tue Nov 17 2009 16:08:06
ghi
jkl
Wed Nov 18 2009 08:11:06
mno
pqr
Thu Nov 19 2009 13:21:56
stu
vwx

I want everything after Tue Nov 17 2009 16:08:06 but get a syntax error. Can someone show me what I am doing wrong?

Code:
 
# awk '/Tue Nov 17 2009 16:08:06/,0' test_file
awk: syntax error near line 1
awk: bailing out near line 1

Figured it might be the : but I also try

Code:
 
# awk '/Tue/,0' test_file
awk: syntax error near line 1
awk: bailing out near line 1

And end up with the same error...
# 2  
Old 11-17-2009
Try

Code:

awk '/Tue Nov 17 2009 16:08:06/ {P = 1} P' test_file

If it's Solaris use nawk or /usr/xpg4/bin/awk
(as we always like to say!)
# 3  
Old 11-17-2009
Code:
 awk '/Tue Nov 17 2009 16:08:06/{p++}(p)' infile
Tue Nov 17 2009 16:08:06
ghi
jkl
Wed Nov 18 2009 08:11:06
mno
pqr
Thu Nov 19 2009 13:21:56
stu
vwx

LOL Smilie
# 4  
Old 11-17-2009
Thanks.
Using nawk fixed it.
# 5  
Old 11-17-2009
Code:
sed '/Tue Nov 17 2009/,$ !d' infile

# 6  
Old 11-17-2009
Code:
sed -n '/Tue Nov 17 2009/,$p' urfile

# 7  
Old 11-18-2009
New question...
How do I print every line after the last occurrence of the pattern?
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