How to define a variable with variable definition is stored in a variable?


 
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# 1  
Old 11-12-2009
How to define a variable with variable definition is stored in a variable?

Hi all,

I have a variable say var1 (output from somewhere, which I can't change)which store something like this:

echo $var1

name=fred
age=25
address="123 abc"
password=pass1234

how can I make the variable $name, $age, $address and $password contain the info?

I mean do this in a simple way rather than

for line in $var1
do
varname=`echo $line | cut -f 1 -d '='`
varvalue=`echo $line | cut -f 2 -d '='`
eval $varname=$varvalue
done

I am looking for something like

. $var1 #I know it is wrong

and then...

echo $name # fred
echo $age # 25
echo $address # 123 abc
echo $password #pass1234

I cannot cat $var1 > tmpfile
. tmpfile
rm tmpfile

because the var1 contain sensitive info e.g. password

Thanks a lot!

Last edited by freddy1228; 11-12-2009 at 04:34 AM.. Reason: cannot delete
# 2  
Old 11-12-2009
Code:
eval $var1

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