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Need help for this monitor log script

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Top Forums Shell Programming and Scripting Need help for this monitor log script
# 1  
Old 11-10-2009
Need help for this monitor log script
this is the format of the log file in my system
Code:
xxxxx_xxx_xxxx_xxxxx_09_10_2009_170457.log
xxxx_xxx_2_0_09_10_2009_163834.log
xxx_xxxxxxxxx_25_10_2009_045020.log
xxx_xxxxxxx_08_11_2009_055728.log

the path of this logs file in on for example
/dellxmax/application/log

what i want to do is
make script
give me this output
----------------------------------------------------------------------
File Name | status | date
----------------------------------------------------------------------
xxxxx_xxx_xxxx_xxxxx_09_10_2009_170457.log | success | 22_10_2009
xxxx_xxx_2_0_09_10_2009_163834.log | success | 22_10_2009
xxx_xxxxxxxxx_25_10_2009_045020.log | success | 22_10_2009
xxx_xxxxxxx_08_11_2009_055728.log | success | 22_10_2009


in this report i want the arrange ascending (the last file modified is the last one in this report)


for the status i want this script search for Successfully in the file
founded give me successfully
if it doesn't give me fail

thanks in advance
# 2  
Old 11-10-2009
Java
try this let me know if it helps, this is assuming you have the "stat" installed

I did this on a CentOS machine. If I understood your post this is what you are looking for just need to tweak it if needed but now you might have the idea.

Code:
#!/bin/bash

counta=1

for file in /dellxmax/application/log/*
do
      DC=$(stat -c %y $file | awk {' print $1'})
        STATUSLOG=$(grep 'success' $file)

        if [ "$?" -eq 0 ]
        then
                ST="success";
        else
                ST="failed";
        fi

        echo "$counta) $file | $ST | $DC";
        counta=`expr $counta + 1`;
done

let me know how it goes
# 3  
Old 11-11-2009
this is the output of the script
Code:
1016) /dellxmax/application/log/xxxxxx_xxxxxx_17_06_2009_041723.log | success | 2009-11-11
1017) /dellxmax/application/log/xxxxxx_xxxxxx_18_09_2009_150922.log | success | 2009-11-11
1018) /dellxmax/application/log/xxxxxx_xxxxxx_23_06_2009_022126.log | success | 2009-11-11
1019) /dellxmax/application/log/xxxxxx_xxxxxx_23_07_2009_030918.log | success | 2009-11-11
1020) /dellxmax/application/log/xxxxxx_xxxxxx_26_08_2009_211545.log | success | 2009-11-11
1021) /dellxmax/application/log/xxxxxx_xxxxxx_28_09_2009_090610.log | success | 2009-11-11
1022) /dellxmax/application/log/xxxxxx_xxxxxx_29_06_2009_034650.log | success | 2009-11-11

1- i appreciate your help very very thank you
2- i need some edit for the output
  • all of this log for the same job run if dufferient days i want to replace 2009-11-11 with the date of the log for example
Code:
1022) /dellxmax/application/log/xxxxxx_xxxxxx_29_06_2009_034650.log | success | 29.06.2009:034650

  • when you run this command ls -ltr all file sorted
    -l long list format
    -t Sorts by time stamp (latest first)
    -r Reverses the order of sort

    So when I do this command the last created depending on time stamp will be the last file in the list
    I want this script have the same concept of the command
  • the script search for successfully else put failed
  • i want to enter another condition and the first condition also running the secand condition is search for dellxmax in the file found write done in the status not found write ndone in the status
totally i would like to thanks you very much for this script
# 4  
Old 11-11-2009
try this:

Code:
#!/bin/bash

counta=1
CMD="ls -tr /dellxmax/application/log/"

for file in `$CMD`
do
      DC=$(echo $file | awk '{ print substr( $0, length($0) - 20, length($0) ) }' | sed 's/.log//g' | sed 's/_/./g')
        STATUSLOG=$(grep 'success' $file)

        if [ "$?" -eq 0 ]
        then
                ST="success";
        else
                ST="failed";
        fi

        echo "$counta) $file | $ST | $DC";
        counta=`expr $counta + 1`;
done

your log files has to be consistent since this will grab the last 21 characters from the log file name, btw, if you want to remove the counta you could and you won't get the line number on each output.

if you need further editing to the script, try doing it yourself and post it here and I will do my best to help you out

let me know if this helped
# 5  
Old 11-11-2009
Code:
#!/bin/bash
set +x
counta=1
TODAY=`date +%d_%m_%Y_`
CMD=`ls -1tr /dellxmax/application/log/*${TODAY}*.log`
for file in $CMD
do
      DC=$(echo $file | awk '{ print substr( $0, length($0) - 20, length($0) ) }' | sed 's/.log//g' | sed 's/_/./g')
        STATUSLOG=$(egrep "success|fine" $file)
        if [ "$?" -eq 0 ]
        then
                ST="success";
        else
                ST="failed";
        fi
        echo "$counta) $file | $ST | $DC";
        counta=`expr $counta + 1`;
done

very thanks for you the script is run and i add to make this script run for today day only
to prevent the previous log file

very thanks for you
thanks last request
i will going to learn shell script
please provide me to good manual for beginner
for shell script & awk % sed
# 6  
Old 11-11-2009
Glad to help.

A book I have "kind of old (2003)" but good, is the "Unix Shell Programming, third edition" Stephen G. Kochan and Patrick Wood

But online you will find many tutorials. You can also browse through unix.com and look at people's problems and see the developed solution and try to analise it.

See you around.
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