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Regex to remove subdirectory

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# 1  
Old 11-03-2009
Regex to remove subdirectory

I need to remove subdirectories that are empty and I've not done this before. First I am going through the files to remove old records. Then if the directory is empty I want to delete it. There are files in /direcotry/images/fs* - 0-9 and a-z The fs* directories need to stay, but any directories under the fs* directories that are empty need to be removed. Did I explain this ok?
So far I have this:
DATESTAMP="`date '+%m%d%y_%H:%M'`"
# this works fine -- 
for file in $( find $DIRECTORY -type f -name '*.tif' -mtime +15 )
  echo $file
  rm -rf $file
done | sort >> "$LOG"

# I can't figure out how to do this- 

for dir in $( find $DIRECTORY -type d -empty )
  echo $dir
  grep [0-9] $dir
#  rm -rf $file
done | sort > "$LOG"

Last edited by pludi; 11-03-2009 at 05:24 PM.. Reason: code tags, please...
# 2  
Old 11-03-2009
Assuming there are only subdirectories in $DIRECTORY that start with "fs", this should work:
find $DIRECTORY/fs*/* -type d -printf "'%p'\n"|sort -r |xargs rmdir 2>&-

# 3  
Old 11-04-2009
There are directories under, so this doesn't work. The directories look like this:

It is these 0900.... directories that need to be removed.
There a literally hundreds of these subdirectories that I need to remove. I guess my question wasn't clear enough. Can you still help me?
# 4  
Old 11-04-2009
Actually I think that should work. You seem to confirm that there are only subdirectories called fs* (e.g. fsa) in $DIRECTORY (/directory/images). These subdirectories must not be removed but the subdirectories inside these subdirectories do have to be removed if they are empty (i.e. contain no files or further subdirectories).

# 5  
Old 11-04-2009
After review, I believe you are right. Thanks,

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