while loop problem


 
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# 1  
Old 11-03-2009
while loop problem

Code:
#!/bin/sh

clear

befehle=( whoami ls who finger ps )
eingabe=5

while [ $eingabe > 4 ]
do
 # for i in 0 1 2 3 4
  #  do
   #   echo  $i - ${befehle[$i]}
  #done
echo "you're still in the loop"
read eingabe
echo "Input:" $eingabe
done

Hello,

I am having a problem with this loop. WHATEVER I give in as an input, it does not exit the loop :s

Last edited by pludi; 11-03-2009 at 06:45 AM.. Reason: code tags, please...
# 2  
Old 11-03-2009
Quote:
you're still in the loop

Input:
ant:/home/vbe/script/091103 $more test001
Code:
#!/bin/sh

clear

befehle="\( whoami ls who finger ps \)"
eingabe=5

while [ "$eingabe" > 4 ]
do
 # for i in 0 1 2 3 4
  #  do
   #   echo  $i - ${befehle[$i]}
  #done
echo "you're still in the loop"
read eingabe
echo "Input:" $eingabe
done

# 3  
Old 11-03-2009
Code:
while [ $eingabe -gt 4 ]

# 4  
Old 11-03-2009
Problem solved, thanks.

I had to use the -gt instead of >
# 5  
Old 11-03-2009
Sorry, your error wasnt clear to me...
And testing again I realized what you wanted and you got the answer before I had time to correct... yes it was -gt like this:
Code:
while [ "$eingabe" -gt 4 ]

# 6  
Old 11-03-2009
Hi vbe,

I never understood the use of "" with this kind of numerical comparison.
If eingabe="" then without them you will get:
Code:
[: -gt: unary operator expected

but with these double quotes you will get:
Code:
[: : integer expression expected

So it seems to me one might as well leave them out, no?

Code:
while [ $eingabe -gt 4 ]

# 7  
Old 11-03-2009
Greetings scrutinizer,
I suppose its a habit from the time HPUX had a shell that was very fussy on syntax especially in tests for my part...

You had to write:
Code:
if test -x "$1"
then
..
if [ "$ANSWER" = y ]
then
...
if [ "$SZ" -le  5000 ]
then
.
.

All the best
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