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for loop in Unix

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# 1  
Old 10-28-2009
for loop in Unix
This is the content of a file work.log
1 TGBUS I-US 0;15;83

i did this
for i in `cat work.log`
do
echo $i
done

I wanted the out put to be
1 TGBUS I-US 0;15;83

But the output appears as
1
TGBUS
I-US
0;15;83

For Loop treats space as a delimiter. Can i overrride this space as delimiter
Can anyone assist
# 2  
Old 10-28-2009
Try this to get rid of the spaces:

Code:
while read i
do
  echo "$i"
done < work.log

# 3  
Old 10-28-2009
This works. But theres no way to do the same with a for loop.

Just out of curiosity.
# 4  
Old 10-28-2009
Code:
for i in "`cat work.log`"
do
echo "$i\n"
done

# 5  
Old 10-28-2009
If i have undertood what you want, i think that:

for i in `cat work.log`
do
echo "$i \c"
done

it could be.

\c : suppress trailing newline
or
echo -n : do not output the trailing newline
# 6  
Old 10-28-2009
I should avoid the use of cat, but if you really want to use the for loop, you can change the IFS temporary like this:

Code:
#!/bin/sh

OLDIFS="$IFS" 

IFS=""

for i in `cat work.log`;do 
  echo "$i"
done

IFS="$OLDIFS"

# 7  
Old 10-28-2009
Quote:
Originally Posted by Franklin52
I should avoid the use of cat, but if you really want to use the for loop, you can change the IFS temporary like this:

Code:
#!/bin/sh

OLDIFS="$IFS" 

IFS=""

for i in `cat work.log`;do 
  echo "$i"
done

IFS="$OLDIFS"

But ..... doesn't he want the output in a unique line ????
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