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date and time in mm/dd/yyyy hh:mm format

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# 1  
Old 10-28-2009
date and time in mm/dd/yyyy hh:mm format
Frens,

I have a logfile which has got manier things in it and somewer in that file i have a date in mm/dd/yyyy hh:mm format....

I just need to get the date and time nothing else....

i have searched in this forum for it but got only date in mm-dd-yyyy format..

but i need to search for mm/dd/yyyy format... i badly in need of it...

please help me bro's.... i think i shud use sed command for this but m very bad in that... pls help me..

Thank you.
Regards
Deepu
# 2  
Old 10-28-2009
Provide a snippet of log file so that the exact cmd can be given
# 3  
Old 10-28-2009
Basically you can use something like this:
Code:
echo "mm-dd-yyyy"| sed 's/-/\//g'
mm/dd/yyyy
# or
echo "mm-dd-yyyy here comes the ultimate-rest"| awk '{gsub(/-/,"/",$1); print}'
mm/dd/yyyy here comes the ultimate-rest

But it might be better if you post a whole line using code tags of your input file.
# 4  
Old 10-28-2009
bro,

i shud not give any particular date while searching bcos the date varies from one logfile to other so i shud extarct the date from logfile... that too in mm/dd/yyyy hh:mm format.. pls help me in this...

EXAMPLE:
Code:
Hi

This is just for example..

This was sent by Ezzat on 10/15/2009 12:48 .....

COnsider this example and do the needful..

Thank you.
Regards.
xxxxxx

so in the above example there is a date and time which i need to extarct.. and this date n time may be different for different logfiles....
Last edited by zaxxon; 10-28-2009 at 03:45 AM.. Reason: use code tags!
# 5  
Old 10-28-2009
Code:
[house@leonov] echo "This was sent by Ezzat on 10/15/2009 12:48 ....." \
[............] | egrep -o "[0-9]{2}/[0-9]{2}/[0-9]{4} [0-9]{2}:[0-9]{2}"
10/15/2009 12:48

# 6  
Old 10-28-2009
Quote:
Originally Posted by dr.house
Code:
[house@leonov] echo "This was sent by Ezzat on 10/15/2009 12:48 ....." \
[............] | egrep -o "[0-9]{2}/[0-9]{2}/[0-9]{4} [0-9]{2}:[0-9]{2}"
10/15/2009 12:48

it is not working for me. Giving error as illegal option -o.

and do I need to use [house@leonov] [............] these 2 things? no right?

Please help me
# 7  
Old 10-28-2009
To get better answers, please give info about your OS environment.

Code:
sed -n 's+.*\([0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9] [0-9][0-9]:[0-9][0-9]\).*+\1+p'

If the "s+...+...+" doesn't work, replace "+" with "/", "/" with "\/".
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