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Remove "/" from a string


 
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# 1  
Old 10-23-2009
Remove "/" from a string

Hi,

I've a string "200910/22-101010" ( this is date and time string YYYYMMDD/HHMMSS format) , how can i remove "/" and assign it to a new variable a value of 20091022 only

thanks
# 2  
Old 10-23-2009
echo 200910/22-101010 | sed "s/\///"
# 3  
Old 10-23-2009

Code:
string=200910/22-101010

temp=${string%-*}
IFS=/ read a b <<EOF
$temp
EOF

newvar=$a$b

# 4  
Old 10-23-2009
Code:
string="200910/22-101010"
 
echo ${string%-*}|tr -d "/"
20091022

For completeness: -

Code:
new_variable=$(echo ${string%-*}|tr -d "/")
echo $new_variable                         
20091022


Last edited by steadyonabix; 10-23-2009 at 04:19 PM..
# 5  
Old 10-23-2009
Code:
foo="200910/22-101010"
foo=${foo%%-*}
foo=${foo//\//}
echo $foo

# 6  
Old 10-23-2009
Code:
ds="200910/22-101010"

posix:
Code:
ds=${ds%-*}
newvar=${ds%/*}${ds#*/}

ksh/bash:
Code:
ds=${ds%-*}
newvar=${ds/\/}

tr:
Code:
newvar=$(echo ${ds%-*}|tr -d '/')

sed:
Code:
newvar=$(echo $ds|sed 's|/||;s|-.*||')
-or-
newvar=$(echo $ds|sed 's|/\(..\).*|\1|')

awk:
Code:
newvar=$(echo $ds|awk -F '[/-]' '{print $1$2}')


Last edited by Scrutinizer; 10-23-2009 at 04:57 PM..
# 7  
Old 10-23-2009
Quote:
Originally Posted by danmero
Code:
foo="200910/22-101010"
foo=${foo%%-*}
foo=${foo//\//}
echo $foo


Code:
$ foo=${foo//\//}
echo $foo$ $ Syntax error: Bad substitution


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