Shell Programming and Scripting

hi, I m stuck at a point for more than 3days. My doubt is pretty simple..
I have a web page content in $content. ( got this by using LWP)..

Now I want to display the content matching a pattern.

I tried

Code:

  if($content =~ m{<div class="abc">(.*?)</div>}s){
   print $1;}

that will display for only 1st pattern match..
Now I want to display content between each <div class="abc"> and </div> occuring in the $content and store in array.

Pls help me out how to do it...
how should i apply the while loop..

thanx..

you will also need the multiline modifier.. see perldoc perlre

what is multiline modifier...
I only want to know how could i apply while loop...
around the if condition so that it searches entire $content..

thankx

Hint 1: The modifier 'g' means 'global'
Hint 2:

Code:

$ echo '/a/ /b/ /c/ /d/' | perl -le '$c=<>; @a=($c=~m{/(.*?)/}g); print "@a";'
a b c d

Hint 3: perldoc perlretut, perldoc perlre

I tried
code:

Code:

@arr=($content =~ m{<div class="abs\c">(.*?)</div>}g);
print @arr;

but when i try putting s instead of g it print the content inside first occuring <div> tags pair in $content..

i still could not figure out the problem...

---------- Post updated at 03:02 AM ---------- Previous update was at 03:00 AM ----------

Code:

@arr=($content =~ m{<div class="abs\c">(.*?)</div>}g);
print @arr;

its not working

---------- Post updated at 03:27 AM ---------- Previous update was at 03:02 AM ----------

I got the it..!!!! jsst put s and g together... as...

Code:

@arr=($content =~ m{<div class="abs\c">(.*?)</div>}sg);
print @arr;