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How to test if part of a string matches?

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# 1  
Old 10-17-2009
Question How to test if part of a string matches?
How to test if the first 7 characters of a string matches "backup."?

This did not work:
Code:
#!/bin/sh
name="backup.20091122"
if [ "${$name | cut -c 1-7}" = "backup." ]
then
    echo name is a backup
else
    echo name is not a backup
fi

Thank you.
# 2  
Old 10-17-2009
Quote:
Originally Posted by wolfv
Code:
if [ "${$name | cut -c 1-7}" = "backup." ]

Code:
if [ "$( echo $name | cut -c 1-7 )" = "backup." ]

# 3  
Old 10-17-2009
Code:
if [ "${name%.*}." = "backup." ]

# 4  
Old 10-17-2009
Code:
[[ $name == @(backup[\.])* ]] && echo yes 
yes



---------- Post updated at 12:44 PM ---------- Previous update was at 12:40 PM ----------

Code:
[[ $name == @(backup[\.][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]) ]] && echo yes
yes

If you want the date as well
# 5  
Old 10-17-2009
works in either bash or ksh93
Code:
name=backup.12345678
[[ ${name:0:7} == backup. ]] && echo "yes"

# 6  
Old 10-17-2009
Code:
# name=backup.12345678
# case $name in backup* ) echo "yes";; esac

# 7  
Old 10-17-2009
Question
Thank you for the wide range of solutions. But what shell are you using? I am using borne shell.

---------- Post updated at 02:08 PM ---------- Previous update was at 01:48 PM ----------
Quote:
Originally Posted by Scrutinizer
Code:
if [ "${name%.*}." = "backup." ]

Where can I learn more about the "%.*" syntax? Or what key words can I google to read about the syntax?

Thank you.
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