Shell Programming and Scripting

hi,

I have the following file

Code:

hello
world
this
is 
to
say
bye
to
everyone
so
bye

I want to get the lines from hello to the first bye inclusive into another file?

how can I do this

thanks

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---------- Post updated at 02:28 PM ---------- Previous update was at 02:26 PM ----------

Code:

sed -n '/hello/,/bye/p' myFile

Don't do it youngster, learn a bit of awk, it will give your life new meaning

Code:

nawk '/bye/{print;exit} /hello/{p=1}p' infile > another.file

thanks, that worked perfectly

HI Can u please tell if i pass the ,

start and end patterns as arguments i mean

Code:

nawk '/$end_Pattern/{print;exit} /$start_Pattern/{p=1}p' infile > another.file

where end_Pattern=bye
start_Pattern=hello

but the above is not working good

Hi.

You're trying to use shell variables inside awk, which doesn't work.

Either use something like:

Code:

awk '/'$start_pattern'/,/'$end_pattern'/' infile

or (taking the steadyonabix example)

Code:

awk -v S=$start_pattern -v E=$end_pattern '$0 ~ E {print;exit} $0 ~ S{p=1}p' infile > another.file

Thaks @scott

The First Command giving the lines along with the start_pattern and end_pattern.
can u please tell me the exact command to output the lines only between the pattern's.