I am attempting to figure out how to do a time check within my script.
For some reason I can not seem to get this to work correctly.
I want the script to first see if it is Saturday.
If it is Saturday then check to see if it's between the time 5:30am and 6:30am.
If it is between 5:30am and 6:30am then exit out of the script.
If it is not between 5:30am and 6:30am then let the script continue.
I just need this script to exit out if it is Saturday between the hours of 5:30am and 6:30am.
I know there are better ways of doing this but I am trying to figure out why the script below is not working.
Thanks for the help.
Code:
#!/bin/sh
day=`date`
time=`echo $day | cut -d" " -f4`
hour=`echo $time | cut -d":" -f1`
minute=`echo $time | cut -d":" -f2`
dayname=`echo $day | cut -d" " -f1`
if [ $dayname = 'Sat' -a $hour = 5 -a $minute -gt 15 ]
then
if [ $dayname = 'Sat' -a $hour = 6 -a $minute -lt 50 ]
then
# Between Sat 5:15 and 6:30, do not continue.
exit
fi
fi
echo "Not between Sat 5:15 and 6:50.... Continue script..."
DAY=$(date '+%w')
TIME=$(date '+%H%M')
[ $DAY -eq 6 -a $TIME -gt 530 -a $TIME -lt 630 ] && exit
echo It's not Saturday between 05:30 and 06:30, so continue...
Your post said 05:30 and 06:30, but your sample code said 05:15 and 06:50?
1. Numeric comparison what you are doing is wrong.. You can use, -eq, -ge, -le.
For this requirement, the following works,
Code:
#!/bin/sh
day=`date`
time=`echo $day | cut -d" " -f4`
hour=`echo $time | cut -d":" -f1`
minute=`echo $time | cut -d":" -f2`
dayname=`echo $day | cut -d" " -f1`
if [ $dayname = 'Sat' -a $hour -ge 5 -a $minute -gt 15 ]
then
if [ $dayname = 'Sat' -a $hour -le 6 -a $minute -lt 50 ]
then
echo "its that time..";
# Between Sat 5:15 and 6:30, do not continue.
exit
fi
fi
echo "Not between Sat 5:15 and 6:50.... Continue script..."
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