Shell Programming and Scripting

Hello,

I want to run a bash script in another bash script, depending on the returncode or exitcode. But I don't know how to handover the returncode to the second bash script!?

I tried this dummy script which should return the exit code 1

Code:

 
#test.sh
echo "test"
exit 1

But catching the returncode and using it in the second script does not work, since I always get the wrong result, namely 0 instead of 1.

Code:

 
#second_script.sh
...
bash test.sh  
if [ $? == 0 ]; then
  echo "fine"
  echo $?
fi
...

Can someone help me?

I'll try to, giving a different example, though:

Script 1

Code:

#! /bin/bash
exit 1

Script 2

Code:

#! /bin/bash
./script1.bash
if [ $? -eq 0 ]
then
  echo "ok"
else
  echo "ko"
fi
echo "$?"
exit 0

Results

Code:

[house@leonov] ./script2.bash
ko
0

The point I'm driving at: $? always refers to the exit state of the last command executed - which in both my and your example is 'echo' (!).

Another approach to illustrate the importance of capturing the reply immediately:

#second_script.sh
...
bash test.sh ; REPLY=$?
echo "REPLY=${REPLY}"

thank you very much, that was very helpful