Bash: Catching the returncode from a script and using within another script?

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# 1  
Old 10-12-2009
Bash: Catching the returncode from a script and using within another script?


I want to run a bash script in another bash script, depending on the returncode or exitcode. But I don't know how to handover the returncode to the second bash script!?

I tried this dummy script which should return the exit code 1

echo "test"
exit 1

But catching the returncode and using it in the second script does not work, since I always get the wrong result, namely 0 instead of 1.

if [ $? == 0 ]; then
  echo "fine"
  echo $?

Can someone help me?
# 2  
Old 10-12-2009
I'll try to, giving a different example, though:

Script 1

#! /bin/bash
exit 1

Script 2

#! /bin/bash
if [ $? -eq 0 ]
  echo "ok"
  echo "ko"
echo "$?"
exit 0


[house@leonov] ./script2.bash

The point I'm driving at: $? always refers to the exit state of the last command executed - which in both my and your example is 'echo' (!).
# 3  
Old 10-12-2009
Another approach to illustrate the importance of capturing the reply immediately:
bash ; REPLY=$?
echo "REPLY=${REPLY}"
# 4  
Old 10-12-2009
thank you very much, that was very helpful Smilie
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