ShellScript Call Function with Directorypath


 
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# 1  
Old 10-08-2009
Question ShellScript Call Function with Directorypath

Hello,

i wrote a code to call a function, the parameter when calling is a path to a directory.
the following code is simular:

Code:
# My Function
check_folder_content()
{
    # ...
}

# Call function for each folder
for myFolder in $(find "${c_my_startpath}SomeSubFolder/" -name "*" -type d)
do
    echo "DEBUG: call function with: ${myFolder}" >> $c_logFile
    check_folder_content "${myFolder}"
done

Now, when getting a Folder like this: "/Blub/SomeSubFolder/Good/Path/aa problem directory" the logFile says:

DEBUG: call function with: /Blub/SomeSubFolder/Good/Path/aa
DEBUG: call function with: problem
DEBUG: call function with: directory

So, the call is definitly wrong (3 times, but never the right path).

What must I change to fix this issue?

Thanks for answers,


Tait
# 2  
Old 10-08-2009
Replace for by while/read :
Code:
# My Function
check_folder_content()
{
    # ...
}

# Call function for each folder
find "${c_my_startpath}SomeSubFolder/" -name "*" -type d | \
while IFS= read myFolder
do
    echo "DEBUG: call function with: ${myFolder}" >> $c_logFile
    check_folder_content "${myFolder}"
done

Jean-Pierre.
# 3  
Old 10-08-2009
Quote:
Originally Posted by Tait
Code:
$(find "${c_my_startpath}SomeSubFolder/" -name "*" -type d)

You'd have to enclose the (full) path within quotes, since otherwise the spaces contained will be interpreted as separators ... how about:

Code:
$(find '"${c_my_startpath}SomeSubFolder/"' -name "*" -type d)

# 4  
Old 10-09-2009
The replacement of for by while as aigles sad was sucessfull.
Thanks a lot!

The quotes dosn't run, also I think i've got the double-quoutes, so that this wasn't the answer.

Best Regards,

Tait
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