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# 1  
Old 10-07-2009
awk question
I want to print the fields of a line to 5 at the end.
I try this code.

Code:
awk '{for(i=5;i<=NF;i++) print $i}' file

But it print each field at new line ???
I try to change the variables (RS,FS,ORS,OFS) without success...

What is the solution ???
# 2  
Old 10-07-2009
Bonjour,

The best is that you post an example of input file and required output. It's easier to understand a request with sample files.

---------- Post updated at 09:08 AM ---------- Previous update was at 09:04 AM ----------

And try printf instead of print.
# 3  
Old 10-07-2009
INPUT

Code:
-rwxr-x---  1 ftp_mont System    343998791 Sep 01 09:20 manif laitiers-H264.mov
-rwxr-x---  1 ftp_mont System     12063097 Sep 27 15:32 Mende_Mende_ITW.mov
-rwxr-x---  1 ftp_mont System       918234 Jun 27 15:44 Mende_Mende_COMJUN.m4a
-rwxr-x---  1 ftp_mont System       918234 Jan 22 15:44 Mende_Mende_COMJAN.m4a
-rwxr-x---  1 ftp_mont System       918234 Jan 20 15:44 Mende_Mende_COMJUN.m4a
-rwxr-x---  1 ftp_mont System       918234 Jan 22 16:44 Mende_Mende_COMJUN.m4a
-rwxr-x---  1 ftp_mont System       918234 Oct 27 15:44 Mende_Mende_COMOCT.m4a
-rwxr-x---  1 ftp_mont System       918234 Sep 27 15:44 Mende_Mende_COM.m4a
-rwxr-x---  1 ftp_mont System    250324761 Sep 27 15:47 Dossier_secheresse-H264-1.mov
-rwxr-x---  1 ftp_mont System    169097455 Sep 27 15:55 Mende_Mende-H264.mov
-rwxr-x---  1 ftp_mont System    343998791 Sep 30 09:20 manif laitiers-H264.mov
-rwxr-x---  1 ftp_mont System    343998791 Sep 30 10:20 manif laitiers1-H264.mov
-rwxr-x---  1 ftp_mont System    343998791 Sep 31 09:20 manif laitiers2-H264.mov

OUTPUT

Code:
343998791 Sep 01 09:20 manif laitiers-H264.mov
12063097 Sep 27 15:32 Mende_Mende_ITW.mo
918234 Jun 27 15:44 Mende_Mende_COMJUN.m4
918234 Jan 22 15:44 Mende_Mende_COMJAN.m4a
918234 Jan 20 15:44 Mende_Mende_COMJUN.m4a
918234 Jan 22 16:44 Mende_Mende_COMJUN.m4a
918234 Oct 27 15:44 Mende_Mende_COMOCT.m4a
918234 Sep 27 15:44 Mende_Mende_COM.m4a
250324761 Sep 27 15:47 Dossier_secheresse-H264-1.mov
169097455 Sep 27 15:55 Mende_Mende-H264.mov
343998791 Sep 30 09:20 manif laitiers-H264.mov
343998791 Sep 30 10:20 manif laitiers1-H264.mov
343998791 Sep 31 09:20 manif laitiers2-H264.mov

# 4  
Old 10-07-2009
Many ways to do this. To use your syntax above:

Code:
awk '{for(i=5;i<=NF;i++) printf "%s%s", $i, (i==NF)?"\n":" "}' infile

This will print either a new line character if i==NF or a space at the end of each field.
# 5  
Old 10-07-2009
Hi.

(if you don't have to use awk...)
Code:
sed ":h s/  / /g;th" file | cut -d" " -f5-

Last edited by Scott; 10-07-2009 at 06:32 AM..
# 6  
Old 10-07-2009
Thank you Ripat....
I do as this....
Code:
awk '{ORS="";for(i=5;i<=NF;i++){if(i==NF){print $i,"\n"} else {print $i," "}}}' file

because i don't "maitrise" the command printf.
# 7  
Old 10-07-2009
Shorter Smilie
Code:
awk '{$1=$1;sub($1FS$2FS$3FS$4FS,"")}1' file
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