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bash, help with stdout manipulation.

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# 1  
Old 10-06-2009
bash, help with stdout manipulation.
Hey all, Im kind of lost on how to do what I want so I figured I would ask.

I want to pipe STDOUT of an app to a log file, but I want to prepend each line of that output with the date and time.

Im drawing a complete blank on how to do this?? Any ideas?

i.e.

output is currently this:

Code:
app is running fine.
synching db files.
corruption found.
blah blah.

to look like this:
Code:
01/01/2009 13:20 - app is running fine.
01/02/2009 05:50 - synching db files.
01/09/2009 22:20 - corruption found.
02/02/2009 00:01 - blah blah.

# 2  
Old 10-06-2009
Hi.

You will get many suggestions I think, but here's one using awk!!

Code:
cat file1 | awk '{"date" | getline A; print A, $0}' > logfile

Tue Oct  6 00:09:42 UTC 2009 app is running fine.
Tue Oct  6 00:09:42 UTC 2009 synching db files.
Tue Oct  6 00:09:42 UTC 2009 corruption found.
Tue Oct  6 00:09:42 UTC 2009 blah blah.

(I put the output you gave into a file (file1) and cat'd it to "simulate" the output of your program. Change the date command to give the format of date you desire)
# 3  
Old 10-06-2009
Code:
app| while read line; do 
  echo $(date '+%m/%d/%Y %H:%M') $line
done> app.log

Replace > with >> if you want the append to the logfile
Last edited by Scrutinizer; 10-06-2009 at 09:09 PM..
# 4  
Old 10-06-2009
These look good... these are the little tricks I need to get better at this junk. Thanks to both of you for the examples.
# 5  
Old 10-06-2009
Code:
cmd |
 while IFS= read -r line
 do
  date "+%m/%d/%Y %H:%M $line"
 done > logfile

# 6  
Old 10-07-2009
Code:
./my_app | xargs -I{} echo $(date "+%m/%d/%Y %H:%M") - {} | tee my_log

# 7  
Old 10-10-2009
Quote:
Originally Posted by cfajohnson
Code:
cmd |
 while IFS= read -r line
 do
  date "+%m/%d/%Y %H:%M $line"
 done > logfile

Thanks, I learned two things, that this is a way to preserved leading and trailing spacing on a line and that you do not need a \ after a | . Smilie
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