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bash, help with stdout manipulation.

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# 8  
Old 10-10-2009
awk '{$0= Date FS $0}1' Date=`date "+%m/%d/%Y %H:%M"` file > newfile

scottn watch for UUOC's Smilie
# 9  
Old 10-10-2009
Hi danmero.

The question was how to format the output of an application to include the date in the output, not just to format an input file like this.

The cat in my original post was to "simulate" the output of the application, not to cat a file as such.

Having said that, I've won a few UUOC awards in my time, for sure!
# 10  
Old 10-10-2009
Originally Posted by trey85stang
I want to pipe STDOUT of an app to a log file, ...
Originally Posted by scottn
The cat in my original post was to "simulate" the output of the application, not to cat a file as such.
Ops, I get the point now. Sorry Smilie

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