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Adding characters at the top of all files in directory

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# 1  
Old 10-06-2009
Adding characters at the top of all files in directory
Hi Unix experts;

I have 30000 files in a directory and am willing to do the following changes on each of them. The input files look like the following:
Code:
1 ,  2
3  ,  4
5  ,  6
7  ,  8
9  ,  10

the output will have # in top 10 lines, insert space instead of comma. This looks like:

Code:
#
#
#
#
#
#
#
#
#
#
1     2
3     4
5     6
7     8
9    10

I have come up with the following. But don't know how I can put # in the first 10 lines:

for file in $(ls -l *)
do
echo $file | sed 's/,/ /g' >output
done

Regards
# 2  
Old 10-06-2009
What about:

bash code:
  1. ls | while read FILE; do
  2. cat << ! > $FILE.new
  3. #
  4. #
  5. #
  6. #
  7. #
  8. #
  9. #
  10. #
  11. #
  12. #
  13. $(sed "s/,/ /" $FILE)
  14. !
  15. cp -f $FILE.new $FILE && rm $FILE.new
  16. done

Or to avoid a UUOC award...
bash code:
  1. ls | while read FILE; do
  2. echo "#
  3. #
  4. #
  5. #
  6. #
  7. #
  8. #
  9. #
  10. #
  11. #
  12. $(sed "s/,/ /" $FILE)
  13. " > $FILE.new
  14. cp -f $FILE.new $FILE && rm $FILE.new
  15. done
Last edited by Scott; 10-06-2009 at 08:47 PM.. Reason: not sure this new highlight=bash thing is working. makes cutting and pasting a real pain
# 3  
Old 10-06-2009
Quote:
Originally Posted by scottn
What about:

bash code:
  1. ls | while read FILE; do
  2. cat << ! > $FILE.new
  3. #
  4. #
  5. #
  6. #
  7. #
  8. #
  9. #
  10. #
  11. #
  12. #
  13. $(sed "s/,/ /" $FILE)
  14. !
  15. cp -f $FILE.new $FILE && rm $FILE.new
  16. done

Or to avoid a UUOC award...
bash code:
  1. ls | while read FILE; do
  2. echo "#
  3. #
  4. #
  5. #
  6. #
  7. #
  8. #
  9. #
  10. #
  11. #
  12. $(sed "s/,/ /" $FILE)
  13. " > $FILE.new
  14. cp -f $FILE.new $FILE && rm $FILE.new
  15. done

That merits a UUOL award. (And it will fail if there are any spaces in any of the filenames.)

Code:
for file in *
do
  {
    printf "%s\n" '#' '#' '#' '#' '#' '#' '#' '#' '#' '#'
    sed 's/,/ /g' "$file"
  } > output && mv output "$file"
done

# 4  
Old 10-06-2009
Thanks for different options! How can i add one space at the beginning of each line while doing the previous task, i.e.
Code:
#
#
#
 1    2
 3    4
 5    6
 6    7
 8    9

The only change is the space befor each data line only

---------- Post updated at 08:15 PM ---------- Previous update was at 08:01 PM ----------

whoops!! I did it by adding another sed!

Thank you very much anyways
Last edited by nxp; 10-06-2009 at 10:03 PM.. Reason: editing
# 5  
Old 10-06-2009
Quote:
Originally Posted by nxp
whoops!! I did it by adding another sed!

You don't need another sed; just another command to the same sed:

Code:
for file in *
do
  {
    printf "%s\n" '#' '#' '#' '#' '#' '#' '#' '#' '#' '#'
    sed -e 's/,/ /g' -e 's/^/ /' "$file"
  } > output && mv output "$file"
done

'Nuff sed!
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