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Shell Programming and Scripting

deleting last n lines from a output

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# 1  
Old 09-30-2009
deleting last n lines from a output
Friends, I am executing this command in solaris sar -d 3 3 | awk 'NR > 2 { if ($1 !~ /,.+/) print }' | egrep -v "nfs[0-9]|device" . Now i want to delete the last two lines of my output as they are records of average which i don't want. can some one pls give me some idea on how to proceed.
# 2  
Old 09-30-2009
try:

Code:
 sar -d 3 3 | awk 'NR > 2 { if ($1 !~ /,.+/) print }' | egrep -v "nfs[0-9]|device" | sed -n '/Average/!p;/Average/q;'

as generic solution to only print lines until Averages

HTH,
# 3  
Old 09-30-2009
not working :-(
# 4  
Old 09-30-2009
Works flawless on my Linux box. Mind to share what is not working?
# 5  
Old 09-30-2009
this is a solaris box. And its working but the sed has to be put first . this is the form in which its working sar -d 3 3 | sed -n '/Average/!p;/Average/q;' | awk 'NR > 2 { if ($1 !~ /,.+/) print }' | egrep -v "nfs[0-9]|device".

Lesson learnt is East or west. Linux the best
# 6  
Old 09-30-2009
This is an awful way of using *nix command. As I already suggested in my answer your earlier post you can do all that without that pipe construction.

sar gives another o/p on my box but I guess that something like this will work:

Code:
sar -d 3 3 | awk '!/device|nfs[0-9]|^,.+|Average/ {printf }'

# 7  
Old 09-30-2009
Way too many pipes for my taste....
Code:
sar -d 3 3 | nawk '!/Average|nfs[0-9]|device/ && FNR>2 && $1 !~ /,.+/ && NF'

Last edited by vgersh99; 09-30-2009 at 09:06 AM..
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