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# 1  
Old 09-29-2009
Join the lines

Hi All,

Currently, the output looks like this:

Code:
hdisk0
queue_depth:3
hdisk1
queue_depth:3
hdisk2
queue_depth:1
hdisk3
queue_depth:1



I need to change the format to look like this:

Code:
hdisk0 queue_depth:3
hdisk1 queue_depth:3
hdisk2 queue_depth:1
hdisk3 queue_depth:1

Thanks very much!

Last edited by vgersh99; 09-29-2009 at 07:49 PM.. Reason: code tags, PLEASE!
# 2  
Old 09-29-2009
Code:
nawk 'ORS=(FNR%2)?FS:RS' myFile

# 3  
Old 09-29-2009
Is that output of your script or a flat file? What is generating this output?
# 4  
Old 09-29-2009
for i in `lspv | awk '{print $1}`
do
print $i
lsattr -El $i | grep queue_depth | awk '{print $1 ":" $2}'
done

The output looks like this

hdisk0
queue_depth:3
hdisk1
queue_depth:3
hdisk2
queue_depth:1
hdisk3
queue_depth:1

how can I change to

hdisk0 queue_depth:3
hdisk1 queue_depth:3
hdisk2 queue_depth:1
hdisk3 queue_depth:1

---------- Post updated at 05:04 PM ---------- Previous update was at 04:54 PM ----------

It works perfectly. Thanks so much vgersh99. You're the guru ! Smilie
# 5  
Old 09-29-2009
instead of

Code:
print $i

you could

Code:
echo -n $i

or

Code:
for i in `lspv | awk '{print $1}`
do
  attribute=`sattr -El $i | grep queue_depth | awk '{print $1 ":" $2}'`
  print $i $attribute
done

# 6  
Old 09-30-2009
Awesome!

Thanks a lot, peterro
# 7  
Old 09-30-2009
Code:
$ sed -n  'N;s/\n/ /p' inputfile
hdisk0 queue_depth:3
hdisk1 queue_depth:3
hdisk2 queue_depth:1
hdisk3 queue_depth:1


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