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How can I use if statement to check a string start with "abc"


 
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# 1  
Old 09-29-2009
How can I use if statement to check a string start with "abc"

I am trying to write a if statement in KSH that if a string is start with abc then print something, I have written some code as below but it doesn't work.
Could someone please help me

if [[ ${name} = "abc*" ]]
then
print success
fi

Last edited by yhever; 09-29-2009 at 01:00 PM..
# 2  
Old 09-29-2009
I believe you can try this if you are using bash
Code:
if [[ ${name:0:3} = "abc" ]] 
then
echo success
fi

# 3  
Old 09-29-2009
I think case is more portable:

Code:
case $name in 
  abc* ) echo success ;;
esac

# 4  
Old 09-29-2009
Quote:
Originally Posted by BubbaJoe
I believe you can try this if you are using bash
Code:
if [[ ${name:0:3} = "abc" ]] 
then
echo success
fi

Thank you BubbaJoe, can I use this in ksh?

---------- Post updated at 11:01 AM ---------- Previous update was at 10:59 AM ----------

Quote:
Originally Posted by radoulov
I think case is more portable:

Code:
case $name in 
  abc* ) echo success ;;
esac

Thank you radoulov
Does it work in ksh, currently my machine hasn't linux env.
# 5  
Old 09-29-2009
Yes it works in ksh
# 6  
Old 09-29-2009
Quote:
Originally Posted by BubbaJoe
Yes it works in ksh
Just to add that the snipped above works with ksh93 and mksh, it doesn't work with ksh88 and pdksh.

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