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# 1  
Old 09-25-2009
awk help

Hi Guys,

I am trying to print all the filenames whose created/modified date is not today.

ts $ ls -lt
total 256
-rw-r--r--   1 fcfmetl  fastcar      116686 Sep 25 06:06 Output_execTVGen.txt
drwxr-xr-x   2 fcfmetl  fastcar         256 Sep 25 05:04 log
-rwxr-xr-x   1 fcfmetl  fastcar        2629 Sep 25 03:03
drwxr-xr-x   2 fcfmetl  fastcar         256 Sep 25 03:00 ftp
-rwxrwxrwx   1 fcfmetl  fastcar        3810 Sep 25 02:48 trigger_execTVGen.ksh
-rw-r--r--   1 fcfmetl  fastcar          88 Sep 24 09:57 email_body.txt
drwxr-xr-x   2 fcfmetl  fastcar         256 Sep 24 09:37 bckup

I am using the below command for it
ls -tl | awk -v f=`date '+%d'` '{if ("$7" -ne "$f" ){print $9}}'

But it is giving all the file name.

Can you let me know where i am going wrong.

# 2  
Old 09-25-2009
Try this solution Smilie
ls -lt | awk -v f=`date '+%d'` '$7 != f && $9{print $9}'

# 3  
Old 09-25-2009
ls -l  | grep "$(date +"%b %d")" | awk '{ print $9 }'

# 4  
Old 09-25-2009
Originally Posted by chakrapani
ls -l  | grep "$(date +"%b %d")" | awk '{ print $9 }'

Did you check the OP requirement ?
Originally Posted by mac4rfree
I am trying to print all the filenames whose created/modified date is not today.
# 5  
Old 09-25-2009
ls -tl | awk -v d=$(date +%d) -v m=$(date +%b) '$6 != d || $7 != m || $8!~/:/'

# 6  
Old 09-25-2009
You can also use find for that.

 find . * -maxdepth 0 -atime +1

# 7  
Old 09-25-2009
Originally Posted by ripat
You can also use find for that.

 find . * -maxdepth 0 -atime +1

This commands doesn't give the required result.
-atime n
File was last accessed n*24 hours ago. When find figures out how many
24-hour periods ago the file was last accessed, any fractional part is
ignored, so to match -atime +1, a file has to have been accessed at least
two days ago.
Replacing -atime +1 by -atime +0 will not give the right result, because find works with hours*24.
A file created yesterday but less than 24 hours ago will not be selected.


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