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shell script, echo doesn't work

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# 1  
Old 09-25-2009
shell script, echo doesn't work
Code:
  #!/bin/sh
  something(){
      echo "Inside something"
      echo $1 $2
  }
  val=$(something "Hello " "world")

Output expected:
Code:
Inside somethingHello world

But it's not echoing.
# 2  
Old 09-25-2009
Code:
$ cat test
  #!/bin/bash
  something(){
      echo "Inside something"
      echo $1 $2
  }
  val=$(something "Hello " "world")
  echo $val

$ ./test
Inside something Hello world

What is the problem ?
# 3  
Old 09-25-2009
Code:
val=$(something "Hello " "world")

This ate away everything ... $( .. made something being executed like any other prg with two parameters. and val got it ... So when you do echo $val ... it shows up ..
# 4  
Old 09-25-2009
This would be better because there are two lines inside $val

Code:
echo "${val}"

Inside something
Hello world

To get the expected output the echo inside the loop must not output a line-feed.

Assumin a normal echo (not the one with the -n switch).

Code:
echo "Inside something\c"


You do get the expected output with just "echo $val" but this is bad practice.
# 5  
Old 09-25-2009
Quote:
Originally Posted by methyl
Assumin a normal echo (not the one with the -n switch).

There is no such thing as a normal echo. There are two major flavours of echo, one which takes the -n option to suppress a trailing newline and the other which uses \c for the same purpose.

There are even versions which accept both forms.

That's why the use of echo is deprecated in favour of printf.
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