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shell script, why isn't if printing message?

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# 1  
Old 09-24-2009
Question shell script, why isn't if printing message?
Why isn't printing message?
Code:
  1 #!/bin/sh
  2
  3 something(){
  4     echo "Inside something"
  5     echo $1 $2
  6 }
  7 val=$(something "Hello " "world")

But it prints.
Code:
  1 #!/bin/sh
  2
  3 something(){
  4     echo "Inside something"
  5     echo $1 $2
  6 }
  7 val=$(something "Hello " "world")
  8 echo $val

Last edited by cola; 09-25-2009 at 02:58 AM..
# 2  
Old 09-24-2009
I don't see any error's Smilie
Code:
# cat script.sh
#!/bin/sh

something(){
    echo "Inside something"
    echo $1 $2
}
val=$(something "Hello " "world")
echo "$val"

# ./script.sh
Inside something
Hello world

# 3  
Old 09-24-2009
Quote:
Originally Posted by danmero
I don't see any error's Smilie
Code:
# cat script.sh
#!/bin/sh

something(){
    echo "Inside something"
    echo $1 $2
}
val=$(something "Hello " "world")
echo "$val"

# ./script.sh
Inside something
Hello world

Yes there is no error.
But the script bellow doesn't display anything.Why?
Code:
  1 #!/bin/sh
  2
  3 something(){
  4     echo "Inside something"
  5     echo $1 $2
  6 }
  7 val=$(something "Hello " "world")

# 4  
Old 09-25-2009
Why should it? You never tell it to. The echos in your function get captured by $(...), and whatever they printed is saved to val.
# 5  
Old 09-25-2009
Bump.
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