Everytime when a specific binaryfile grows (in 4 byte steps) I want to get the newest 2 bytes immediately when they occur. That can be done by
Code:
tail -f binfile
but I need the bytes in hex format. Therefore I use hexdump
Code:
tail -f binfile | hexdump -x
what only prints out complete lines of 16 bytes. But I need the last bytes immediately when the binfile grows not waiting until 16 bytes are reached. So I tried
Code:
tail -c 2 binfile | hexdump -x
where hexdump prints the last 2 bytes only but tail stops after that and does not check the binfile constantly.
I put this into a loop, checking the binfile for changes in filesize
Code:
while [ ]
do
newsize=$(ls -l $binfile | awk '{print ($5)}')
if [ $newsize != $oldsize ]
then
hexchar=$(tail -c 2 $binfile | hexdump -x)
fi
done
So, in principle this works but I think this is no good style and performance optimized, is it? Any ideas how to convert the byte directly out of tail -f binfile ?
Last edited by maloe; 09-10-2009 at 04:39 PM..
Reason: tail [COLOR="Red"][B]- f[/B][/COLOR]
Output is line by line. If every 2 seconds 4 new bytes "xxxx xxxx" are appended to the binary file, then every new output line is printed after 8 seconds.
But what I need is the "xxxx xxxx" immediately. So it should be somthing like
Now there is no output at all. It's not as simple as reformating the the last line. The problem is, that hexdump collects all bytes until a comlete row of 16 byte is printed. When I use hexdump -n4 then it outputs the last 4 bytes, but tail -f stops running :-(
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dynamically convert last binary byte