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find out line number of matching string using grep

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# 8  
Old 09-09-2009
Quote:
Originally Posted by panyam
use "$v" instead of "v" in sed.


in awk something like this :

Code:
awk '/pattern/ {p=1;next} p--' file_name.txt

Thanks man but it is not working. In case of sed it gives me following message
sed: -e expression#1, char3 : expected newer vesrion of sed.
for command
set v=8
sed -n '$vp' file
# 9  
Old 09-09-2009
Quote:
Originally Posted by sarbjit
can you please provide me code to display the contents of next line
Code:
awk '/ABC/{getline;print}' file

# 10  
Old 09-09-2009
Quote:
Originally Posted by Franklin52
Code:
awk '/ABC/{getline;print}' file

thanks man, it is working perfect now

---------- Post updated at 01:47 PM ---------- Previous update was at 12:51 PM ----------
Quote:
Originally Posted by sarbjit
thanks man, it is working perfect now
Can you please tell me if i have to print specific line number from the found pattern. Eg, if i have found pattern on line 6 , i need to print next to next line or say third line from the found pattern
# 11  
Old 09-09-2009
Hi sarbjit,
sed -n "$vp" file won't work as shell will search for value of vp variable instead of variable v. Try this.
sed -n "${v}p" file
Also if you have multiple matches of the search string & you need line no of first match try this:
v=`awk '/searchtext/{print NR ; exit}' file`
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