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To add a number at the end of the line

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# 1  
Old 08-29-2009
To add a number at the end of the line

Hi Folks,

Using the Vi, how can I add a numbers at the end of the line.
For eg: I have the numbers in the file as:

I need to add .0/8 at the end of all the line. So, it should be like
# 2  
Old 08-29-2009


# 3  
Old 08-29-2009
Its worked out, thanks a bunch...
# 4  
Old 09-22-2009

There are ip with double ..


How can I change this to single dot...


Last edited by vgersh99; 09-22-2009 at 10:15 AM.. Reason: code tags, PLEASE!
# 5  
Old 09-22-2009
Try this...

awk -v OFS="" '{print $1,".0/8"}' file

---------- Post updated at 05:28 AM ---------- Previous update was at 05:17 AM ----------

And for the IP double...

awk  '{gsub("[.]{2}",".",$0)}1' file

# 6  
Old 09-22-2009
You can use sed
sed 's/\.$//;s/.*/&.0\/8/' file

or awk
awk -F. '{$0=((!$NF)?$0:$0FS)"0/8"}1'  file

# 7  
Old 09-22-2009
Thanks a lot, it worked out..

Now, I would like to automate the process via cron;

Here below the last log from the server:

stybloga ftpd20571 ::ffff:80.99.99. Sun Sep 20 08:52 gone - no logout
stybloga ftpd20569 ::ffff:79.117.15 Sun Sep 20 08:52 gone - no logout
stybloga ftpd20568 ::ffff:95.223.19 Sun Sep 20 08:52 still logged in
stybloga ftpd20553 ::ffff:188.27.12 Sun Sep 20 08:51 gone - no logout
stybloga ftpd20552 ::ffff:85.66.149 Sun Sep 20 08:51 gone - no logout
stybloga ftpd20550 ::ffff:84.227.20 Sun Sep 20 08:51 gone - no logout
stybloga ftpd20534 ::ffff:89.102.22 Sun Sep 20 08:51 gone - no logout
stybloga ftpd20518 ::ffff:89.173.62 Sun Sep 20 08:51 gone - no logout
stybloga ftpd20511 ::ffff:94.19.144 Sun Sep 20 08:51 gone - no logout
stybloga ftpd20509 ::ffff:89.103.12 Sun Sep 20 08:51 gone - no logout
stybloga ftpd20508 ::ffff:86.101.22 Sun Sep 20 08:51 gone - no logout
stybloga ftpd20507 ::ffff:80.2.176. Sun Sep 20 08:51 gone - no logout

Where :
stybloga -> is the username
::ffff:80.2.1 -> ip address connected to the users.

What I am doing right now is

1) last | grep stybloga | awk '{print $3}' > one
2) awk -F. '{$0=((!$NF)?$0:$0FS)"0/8"}1' one > ipblck
3) Using the bash script, I will block the ip's
IPS=$(grep -Ev "^#" $BLOCKDB)
for i in $IPS
iptables -A INPUT -s $i -j DROP
iptables -A OUTPUT -d $i -j DROP

So, now what I am trying is, there are different user like the same as above using different ip adderss.

1) Need to check the users in the last log, if a user count exceeds more than of 10 times,
2) Then it should check the third value, which is the ip address . If that do differs with different ip address for the 10 counts then
3) then the ip address should be taken and do as like the process what I have mentioned above.. the 3 steps that I am doing now..

I hope it make sense...


Last edited by gsiva; 09-22-2009 at 12:59 PM..

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