awk-adding a column to a file

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# 1  
Old 08-27-2009
awk-adding a column to a file

Hello Friends,

i used awk to sum up total size of files under a directory (with the help of examples, threads here).

ls -l | awk '/^-/ {total += $5} END {printf "%15.0f\n",total}' >> total.txt

After each execution of the script total result is appended into a text file:

i would like to add the execution date of the script into first column and then the results to the second column, but i couldnt do it after some tries. Do you know how to modify the script to add the date (date format is not important)?

Aug 27 7010
Sep 27 7794
Oct 27 8890

thanks by advance
# 2  
Old 08-27-2009
not sure what you meant by 'execution date of the script', but...
ls -l | awk '/^-/ {a[$6 OFS $7]+=$5} END {for(i in a) printf "%s %15.0f\n",i,a[i]}'

ls -l | awk '/^-/ {a[$6 OFS sprintf("%2d",$7)]+=$5} END {for(i in a) printf "%s %15d\n",i,a[i]}'

Last edited by vgersh99; 08-27-2009 at 04:32 PM..
# 3  
Old 08-27-2009
ls -l | awk '/^-/ {total +=$5} END {"date \"+%b %_d\""|getline d;printf "%s %15.0f\n",d,total}' >> total.txt

# 4  
Old 08-27-2009
Hi Vgersh,

with "execution date of script" i meant the date when crontab run the script (monthly). Sorry for my bad explanation.. Let me try the scripts, thnx all
# 5  
Old 08-27-2009
ls -l | awk '/^-/ {total+=$5} END {printf "%s %15d\n",d, total}' d=$(date '+%b %d')

# 6  
Old 08-27-2009
Vgersh i tried it and AWK tries to open 27 of "Aug 27" and give error like below:

#!/bin/ksh -x
ls -l | awk '/^-/ {total+=$5} END {printf "%s %15d\n",d, total}' d=$(date '+%b %d')

+ ls -l
+ date +%b %d
+ awk /^-/ {total+=$5} END {printf "%s %15d\n",d,total} d=Aug 27
awk: can't open 27

and besides i tried Danmero's script, it resulted with this (all script is 1 line so how can i trace it? ):

awk: syntax error near line 1
awk: illegal statement near line 1

# 7  
Old 08-27-2009
ls -l | awk '/^-/ {total+=$5} END {printf "%s %15d\n",d, total}' d="$(date '+%b %d')"

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