Shell Programming and Scripting

Hi,

I understand either AWK or SED can do this, but I not sure how to extract the following configuration in section. Meaning when I need to find code with " ip helper-address 192.168.11.2" , it would start from "interface Serial0/0" and "interface FastEthernet0/1". Only displaying both section by chunk.

If anyone can point me in the right direction , it would be great. Thanks.

Sample configuration
===========================================
!
interface FastEthernet0/0
description R2 Fa0/0
ip address 192.168.1.1 255.255.255.0
duplex auto
speed auto
!
interface Serial0/0
description R2 Se0/0
bandwidth 2000
ip address 192.168.11.1 255.255.255.0
ip helper-address 192.168.11.2
encapsulation ppp
!
interface FastEthernet0/1
description LAN interface
ip address 10.1.1.1 255.255.255.0
ip helper-address 192.168.11.2
duplex auto
speed 10
!
interface Serial0/1
no ip address
shutdown
!
router eigrp 1
network 10.1.1.0 0.0.0.255
network 192.168.1.0
network 192.168.11.0
no auto-summary
!
===========================================

Expected results :
===========================================
interface Serial0/0
description R2 Se0/0
bandwidth 2000
ip address 192.168.11.1 255.255.255.0
ip helper-address 192.168.11.2
encapsulation ppp
!
interface FastEthernet0/1
description LAN interface
ip address 10.1.1.1 255.255.255.0
ip helper-address 192.168.11.2
duplex auto
speed 10
!

Code:

$ awk 'BEGIN { RS = ORS = "!"; FS="\n"; } /ip helper-address 192\.168\.11\.2/ { print $0 }' filename

Thanks a million agn, this would save me hours of manually looking/ctrl+F through the configurations

this forum rocks and so does AWK