Shell Programming and Scripting

-0.1194983E+03 0.6000011E+02
-0.1194394E+03 0.6000006E+02
-0.1195464E+03 0.6000011E+02 <-------- A
-0.1195464E+03 0.6000011E+02 <-------- A'
-0.1195002E+03 0.6000021E+02
-0.1194394E+03 0.6000006E+02 # END
-0.1065872E+03 0.5324551E+02
-0.1100000E+03 0.6000000E+02
-0.1099966E+03 0.6000000E+02 <-------- B
-0.1099966E+03 0.6000000E+02 <-------- B'
-0.1090837E+03 0.6000000E+02 <-------- C
-0.1090837E+03 0.6000000E+02 <-------- C'
-0.1090004E+03 0.6000012E+02
....
-0.1194394E+03 0.6000006E+02 # END

Originally Posted by Franklin52

You can remove the double lines first with uniq and pipe the result to the awk command:

Code:

uniq file | awk '
{s=n?s " " c++:c++; n++}
/# End/{print "NumberOfLines " n; print s "\n"; n=0; s =""}
'

Regards

data file
1
1.23 2.33 1.34
1.33 2.67 4.65
3.56 3.78 1.34
END
2 <-- to be removed
4.67 3.78 6.78 <-- to be removed
6.21 5.55 4.90
3.45 2.57 2.78
3.67 3.71 6.78
END
3 <-- to be removed
3.56 4.89 3.45 <-- to be removed
2.31 6.67 8.90
...

Originally Posted by Cham

Okay, I have one more problem to solve with Awk (or any other simple method in UNIX) :

I have to remove some lines in the data. The original data have the following shape :



The two first lines after "END" should be removed. How can I do that ? Any idea ?

Originally Posted by vgersh99

nawk 'c&&c--{next} /END/ {c=2}1' myFile

Originally Posted by Cham

Thanks. This is working well, but only if I use awk (and not nawk, which isn't recognized on my system).

What is the logic behind this code ? What if we want to remove only 1 line, or three lines ?

Sorry if I'm such a noob !