Shell Programming and Scripting

I need a scriptto print only those files from a list of files starting with STMT* which are not of zero bytes ...i.e they have some size

if these are the files
631
-rw-r--r-- 1 assrisa assrisa 39099 Aug 19 07:16 STMT_05_D1090819_T071320
-rw-r--r-- 1 assrisa assrisa 0 Aug 19 07:21 STMT15022_05_D1090819_T071
637
-rw-r--r-- 1 assrisa assrisa 0 Aug 19 07:46 STMT_05_D1090819_T074311
-rw-r--r-- 1 assrisa assrisa 0 Aug 19 07:51 STMT15022_05_D1090819_T07

the output should be STMT_05_D1090819_T071320

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Is this list generated from a find or ls? If yes you might want to optimize that find.
Else you can do something like this:

Code:

$> awk '$5 != "0" && $NF ~ /^STMT_05_D1090819_T071320$/ {print}' infile
-rw-r--r-- 1 assrisa assrisa 39099 Aug 19 07:16 STMT_05_D1090819_T071320

Hi,

Code:

 
$find . -name "STMT*" ! -empty -exec ls -ltr {} \;
-rw-r--r--    1 scripter     scripterworld        401 Aug 19 21:47 ./STMT_1
 
$ find . -name "STMT*"  -empty -exec ls -ltr {} \;
-rw-r--r--    1 scripter     scripterworld        0 Aug 19 21:47 ./STMT_2

find command empty option displays files with zero bytes So using not " ! " symbol ,we will get files with some size