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to remove the last column


 
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# 8  
Old 08-13-2009
Awk clause.. but it assumes that the bit to be wacked is an "AND" clause....


{
n=split($0, line)
for(i = n; i > 0 ; i--)
if ( line[i] == "AND")
break;
for(n = 1; n < i; n++)
printf "%s ", line[n]

print ";"
}
# 9  
Old 08-14-2009
perl:
Code:
perl -ne '{s/AND(?!.*AND.*$).*//;print;}'

# 10  
Old 08-14-2009
Guys,, both the perl and awk commands worked fine.. actually i do not know perl..

@jp2542a, can you please explain your awk command.. that really help me in better understanding of awk.. i am learning awk..

Thanks for your help guys
# 11  
Old 08-14-2009
Just bash and parameter expansion Smilie
Code:
#!/bin/bash
# read line < file

# echo $line
UPDATE TRDSTG.STRDCLM2 SET C_TREAD_COMPONENT='NR', X_MEMO_REF='M:LOP8 F 2009' WHERE C_SOURCE='CSC' AND D_QTR_APPLBTY=200902 AND I_DOCUMENT=381917678 AND C_TREAD_COMPONENT='GP' AND C_SFTY_CSQ='W08J01182' AND X_MEMO_REF='G:LOP8 F 2009';

# echo ${line%\ AND\ *}
UPDATE TRDSTG.STRDCLM2 SET C_TREAD_COMPONENT='NR', X_MEMO_REF='M:LOP8 F 2009' WHERE C_SOURCE='CSC' AND D_QTR_APPLBTY=200902 AND I_DOCUMENT=381917678 AND C_TREAD_COMPONENT='GP' AND C_SFTY_CSQ='W08J01182'

# 12  
Old 08-14-2009
cool danmero..

Can you tell me what your code does?

@jp2542a, using split command spliting the line and storing the number of words in n
and after that you are reducing the value of i until u get AND and then your printing before AND. Please correct me if i am wrong..
# 13  
Old 08-14-2009

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