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# 1  
Old 08-13-2009
perl required output
Hi,

I have a string in log file from that i need to pick the username.

the string is like this--

Code:
pid 2172 tid 3124: 160: 10110847: userName :[app@abc.com]
pid 2172 tid 3124: 160: 10110847: userName :[napp@abc.com]
pid 2172 tid 3124: 160: 10110847: userName :[12345]
pid 2172 tid 3124: 160: 10110847: userName :[app@abc_sde.com]
pid 2172 tid 3124: 160: 10110847: userName :[567890]
pid 2172 tid 3124: 160: 10110847: userName :[dfgehj]

Note: I get so many lines in between the above snippet. this is just a snippet.

I want to take all the usernames here in the snippet. The code i have gives only the numeric part.

The output i am expecting is --

Code:
app@abc.com
napp@abc.com
12345
app@abc_sde.com
[567890
dfgehj

Suggest to handle special characters in the username.

Thanks
NT
Last edited by namishtiwari; 08-13-2009 at 09:13 AM.. Reason: output was wrong so corrected it.
# 2  
Old 08-13-2009
Code:
perl -ne '/(userName :.*)/; print $1,"\n";' logfile

# 3  
Old 08-13-2009
I tried this option already and it did not work for me.

some part of my code is like this--

Code:
for(;$index<@records;$index++)
	{
		#printf "LINENO=$index\n";
		
		if ($records[$index] =~ /userName\s+:\[(..*)\]/)
		{
			$User_Name = $1;
			print "User_Name before concatenation is = $User_Name\n";
			$User_Name =~ s/\s+//g;
			$User_Name= "'"  .   $User_Name     .  "'";
			print "User_Name = $User_Name\n";}

I never got the deisred result in my case.


Thanks
NT
# 4  
Old 08-13-2009
ahh... reg exp
Use this expression to match [usernames]
Code:
$line =~ /(\[.*\])/;

And then do this to remove the brackets
Code:
$line2 =~ s/(\[|\])//;

# 5  
Old 08-14-2009
Quote:
Originally Posted by chompy
Use this expression to match [usernames]
Code:
$line =~ /(\[.*\])/;

And then do this to remove the brackets
Code:
$line2 =~ s/(\[|\])//;

Does this make a diffrence as i am doing both in one.

Thanks
NT
# 6  
Old 08-14-2009
I suspect the problem is not what you think it is because your code works fine with your data, for me anyway:

Code:
while(<DATA>){
   if (/userName\s+:\[(..*)\]/){
      $User_Name = $1;
      print "User_Name before concatenation is = $User_Name\n";
      $User_Name =~ s/\s+//g;
      $User_Name= "'"  .   $User_Name     .  "'";
      print "User_Name = $User_Name\n";
   }
}

__DATA__
pid 2172 tid 3124: 160: 10110847: userName :[app@abc.com]
pid 2172 tid 3124: 160: 10110847: userName :[napp@abc.com]
pid 2172 tid 3124: 160: 10110847: userName :[12345]
pid 2172 tid 3124: 160: 10110847: userName :[app@abc_sde.com]
pid 2172 tid 3124: 160: 10110847: userName :[567890]
pid 2172 tid 3124: 160: 10110847: userName :[dfgehj]

and the output is:

Code:
User_Name before concatenation is = app@abc.com
User_Name = 'app@abc.com'
User_Name before concatenation is = napp@abc.com
User_Name = 'napp@abc.com'
User_Name before concatenation is = 12345
User_Name = '12345'
User_Name before concatenation is = app@abc_sde.com
User_Name = 'app@abc_sde.com'
User_Name before concatenation is = 567890
User_Name = '567890'
User_Name before concatenation is = dfgehj
User_Name = 'dfgehj'

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