Shell Programming and Scripting

Hello,

i have a file "Movie.ini" looking e.g. like follows

Code:

* MOVIE A
bla bla
MOVIE B
blubb blubb
MOVIE C

I'd like to read the file "Movie.ini" with cat and grep and check whether it includes the string MOVIE only with a '*' at the beginnig.

By doing

Code:

"cat Movie.ini| grep MOVIE >> tmp_MOVIE "

all rows containing MOVIE should be saved in a tempfile

Code:

* MOVIE A
MOVIE B
MOVIE C

I have following problem, since I just know a bit ksh but not bsh:

1. How can I read out the rows of the file "tmp_MOVIE" in a VARIABLE long / dynamic allocated array? (Since there is NOT a fix number of rows containing the string MOVIE - it can be 3, 5 or e.g. 20)
2. How can I check the first literal of an array-element whether it is a '*'?

Thanks a lot for any helpful answer

Please use CODE tags next time when displaying code, data or logs to enhance readability and to preserve formatting like indention etc., ty.

I believe that one grep would be sufficient:

Code:

grep '^* MOVIE' Movie.ini

Hello Thanks,

I'll try it, but how can I handle assigning a dynamic number of stings into arrays?

Why do you think you need an array?

I want to read out ALL appearances of the string 'Movie' and check whether they ALL beginn with a '*'. So I think I need an array with a DYNAMIC number of fields since they number of 'Movie'-string varies.

grep will search for the pattern specified in it ( "^ * MOVIE" in your case ) in the whole file and whenever it finds, it will print the whole line.

so you don't need array.

Code:

man grep

for more details. also

Code:

man regex

But I think I need an array, because I want to check within a script if there is MOVIE without '*' and if there is a MOVIE without '*', a mail will be send. That part is already written and running, I just need a working if-clause.