Shell Programming and Scripting

Guys,

Could you please help me out. I need two values in two variables using awk from the o/p of grep.

example:-

grep sdosanjh <filename>
sdosanjh myhostname myfilename

NOW WHAT I WANT IS :-
sdosanjh should be in variable (say NAME)
myhostname should be in variable (say HOSTNAME)

3rd coloumn i am not bothered about.

Can you please suggest if we can do this by pipe the output of grep to awk ?

I tried the following but not able to get the value of val1 using echo.

grep sdosanjh <filename> | awk '{val=$1}{val1=$2}{print val, val1}'

Because my next line will be making a ssh connection with the myhostname
i.e. ssh $val1 [Something like that]

yes you can use awk...

Code:

NAME=`awk '/sdosanjh/{print $1}' filename`
HOSTNAME=`awk '/sdosanjh/{print $2}' filename`

Code:

set `grep sdosanjh filename`
echo $1 $2 $3

You need to provide test for failure otherwise you will get some gibberish.
these are called positional parameters and there are 9 of them. To have more you need to use shift command.
There is no need to use awk here.
Another interesting construct for long file is:

Code:

cat filename | grep sdosanjh |
while read var1 var2 var3
do
echo $var1 $var2 $var3
done

If you have less variables than items, all remainder of the read line gets packed into var3

thnaks gch... your solution looks good and working fine...

That construct is very powerful, and permits also to rearrange order of strings in a file.
You could do:

Code:

....
do
echo $var3 $var2 $var1 >> newfile
done
....

Gch,

Good solution. A bit modification :

Code:

grep sdosanjh filename |
while read var1 var2 var3
do
echo $var1 $var2 $var3
done

This is how it should be done in this particular case. Mine just illustrates, for less experienced, the fact that you can chain several commands before that while.