Login or Register to Ask a Question and Join Our Community


Shell Programming and Scripting

(g)awk how to preseve white spaces (FS characters) or read a right subpart of $0?

Login to Discuss or Reply to this Discussion in Our Community

 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting (g)awk how to preseve white spaces (FS characters) or read a right subpart of $0?
# 8  
Old 07-28-2009
Maybe something like this could work for you:
Code:
ls -ltr | awk 'BEGIN{FS=" [[:digit:]][[:digit:]]:[[:digit:]][[:digit:]] "}{print $2}'

# 9  
Old 07-28-2009
Quote:
Originally Posted by thanhdat
Maybe something like this could work for you:
Code:
ls -ltr | awk 'BEGIN{FS=" [[:digit:]][[:digit:]]:[[:digit:]][[:digit:]] "}{print $2}'

Assuming the filenames do not contain the pattern you use as a field separator ...
# 10  
Old 07-28-2009
yeah, you're right, the filename must not contain the FS °___°
# 11  
Old 07-28-2009
Quote:
Originally Posted by shri_nath
...
With regular expressions (pattern matching) I am ignoring all the lines except the ones which are NOT directories with long listing format.

So I consider only:
-rwxrwxrwx 1 sn sn 15348 2007-05-11 08:37 This is a file name with seven spaces.jar*
-rwxrwxrwx 1 sn sn 22395 2007-05-11 08:37 This is a file name with eighteen spaces.jar*
-rwxrwxrwx 1 sn sn 73687 2007-05-11 08:37 ibmjcefw.jar*
-rwxrwxrwx 1 sn sn 767101 2007-05-11 08:37 ibmjceprovider.jar*
Question is: How do I get the file names with preserving the white spaces in between?
...

Or making use of the fact that the files' timestamp is a pattern found first before the filenames and its length is fixed, another alternative would be:


Code:
awk '/^-[rwx-]/{ print substr($0,match($0,/[0-2][0-9]:[0-5][0-9]/)+6) }' file

# 12  
Old 07-28-2009
Hi radoulov,

Quote:
Originally Posted by radoulov
You know that the filename will be after the 7th field,
so you could do something like this:

Code:
gawk --posix 'NR > 2 && !/\/$/ {
  sub(/([^ \t]+[ \t]+){7}/,"")
  print
  }' infile

This is the best answer. I had also come to the same pattern, but albeit separately for each of the first seven fields. Your answer is even better. I am going to change it a little bit as follows:

Code:
     gsub(/^([^ \t]+[ \t]+){6}[^ \t]+ /, "", fileName);

for the obvious reason that fileName itself could start with a white space!
Could you suggest me a pattern that would also get rid of the very last (one or zero) characters from these: />*|@= ?

I tried
Code:
    gsub(/^([^ \t]+[ \t]+){6}[^ \t]+ (.+)[\/\>\*\|\@\=]{0,1}$/, "\\1", fileName);

but that did not work and so I am having the above left most seven fields removed first and then followed by another to gsub to remove the (zero or one) of those last charcters.
Thanks.

-sn
# 13  
Old 07-28-2009
Quote:
Originally Posted by shri_nath
Hi radoulov,



This is the best answer. I had also come to the same pattern, but albeit separately for each of the first seven fields. Your answer is even better. I am going to change it a little bit as follows:

Code:
     gsub(/^([^ \t]+[ \t]+){6}[^ \t]+ /, "", fileName);

for the obvious reason that fileName itself could start with a white space!
Could you suggest me a pattern that would also get rid of the very last (one or zero) characters from these: />*|@= ?

I tried
Code:
    gsub(/^([^ \t]+[ \t]+){6}[^ \t]+ (.+)[\/\>\*\|\@\=]{0,1}$/, "\\1", fileName);

but that did not work and so I am having the above left most seven fields removed first and then followed by another to gsub to remove the (zero or one) of those last charcters.
Thanks.

-sn
Did you test this code? Does this not work for you?
It takes care of even the last bit thing, the *.
Code:
ls -ltr | sed -n '/^-/ s/^.*[0-9] \(.*\)$/\1/p'

# 14  
Old 07-28-2009
i think perl can help you some

Code:
while(<DATA>){
	#print $1,"\n" if /EXL.*(KOSBND_EXC_[^ ]*)/;
	my @tmp = split(" ", $_, 8);
	print $tmp[7];
}
__DATA__
-rwxrwxrwx 1 sn sn 15348 2007-05-11 08:37 This is a file name with seven spaces.jar*
-rwxrwxrwx 1 sn sn 22395 2007-05-11 08:37 This is a file name with eighteen spaces.jar*
-rwxrwxrwx 1 sn sn 73687 2007-05-11 08:37 ibmjcefw.jar*
-rwxrwxrwx 1 sn sn 767101 2007-05-11 08:37 ibmjceprovider.jar*
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Removing blank/white spaces and special characters

Hello All , 1. I am trying to do a task where I need to remove Blank spaces from my file , I am usingawk '{$1=$1}{print}' file>file1Input :- ;05/12/1990 ;31/03/2014 ; Output:- ;05/12/1990 ;31/03/2014 ;This command is not removing all spaces from... (6 Replies)
Discussion started by: himanshu sood
6 Replies

2. Shell Programming and Scripting

Bash - read white spaces

Hello! I have one problem with my bash script - I would like to be able to read white space characters from stdin (for example single " ") - can I acomplish that somehow? I need to read only one character at the time, so I use read -s -n 1 var but it doesn't work for whitespaces apparently. ... (3 Replies)
Discussion started by: xqwzts
3 Replies

3. AIX

Replace all TAB characters with white spaces

Dear Gurus Can you please advise me on how to Replace all TAB characters with white spaces in a text file in AIX? Either using vi or any utilities (2 Replies)
Discussion started by: tenderfoot
2 Replies

4. Shell Programming and Scripting

Leading white spaces

Hi, I am having problem in deleting the leading spaces:- cat x.csv baseball,NULL,8798765,Most played baseball,NULL,8928192,Most played baseball,NULL,5678945,Most played cricket,NOTNULL,125782,Usually played cricket,NOTNULL,678921,Usually played $ nawk 'BEGIN{FS=","}!a... (2 Replies)
Discussion started by: scripter12
2 Replies

5. Solaris

removing special characters, white spaces from a field in a file

what my code is doing, it is executing a sql file and the resullset of the query is getting stored in the text file in a fixed format. for that fixed format i have used the following code:: Code: awk -F":"... (2 Replies)
Discussion started by: priyanka3006
2 Replies

6. UNIX for Dummies Questions & Answers

Replace only first found white spaces with some other characters

Anybody can help me How can I replace only four first white spaces with , or any other characters aaaa 08/31/2004 08/31/2009 permanent Logical Processors in System: 64 bedad 08/16/2001 08/15/2011 permanent Logical Processors in System: 64 badnv14 05/31/2008 05/30/2013 permanent Logical... (5 Replies)
Discussion started by: pareshan
5 Replies

7. Shell Programming and Scripting

trimming white spaces

I have a variable that calls in a string from txt file. Problem is the string comes with an abundance of white spaces trailing it. Is there any easy way to trim the tailing white spaces off at the end? Thanks in advance. (9 Replies)
Discussion started by: briskbaby
9 Replies

8. Shell Programming and Scripting

Trim white spaces using awk

Hi, I have a CSV file with footer information as below. The third value is the number of records in the file. Sometimes it contains both leading and trailing white spaces which i want to trim using awk. C,FOOTER , 00000642 C,FOOTER , 00000707 C, FOOTER,... (2 Replies)
Discussion started by: mona
2 Replies

9. Shell Programming and Scripting

delete white spaces

hi all... i have the next question: i have a flat file with a lot of records (lines). Each record has 10 fields, which are separated by pipe (|). My problem is what sometimes, in the first record, there are white spaces (no values, nothing) in the beginning of the record, like this: ws ws... (2 Replies)
Discussion started by: DebianJ
2 Replies

10. UNIX for Dummies Questions & Answers

deleting white spaces

How would I delete white spaces in a specified file? Also, I'd like to know what command I would use to take something off a regular expression, and put it onto another. ie. . . . expression1 <take_off> . . . expression2 (put here) . . . Any help would be great, thanks! (10 Replies)
Discussion started by: cary530
10 Replies
Login or Register to Ask a Question