How to loop through every char in a string

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Top Forums Shell Programming and Scripting How to loop through every char in a string
# 1  
Old 07-23-2009
How to loop through every char in a string

for example this string: gLZMQp8i

Loop become easy if we add space between each char, How to do it?
or other solutions are welcome.
# 2  
Old 07-23-2009
What you want to do in the loop?
# 3  
Old 07-23-2009
echo 'gLZMQp8i' | sed 's|.|&\n|g'

# 4  
Old 07-23-2009
I have found this code....

var="example text";var1=$(echo $var | wc -c);for((i=$var1;i>=0;i--));do echo $var | cut -c $i;done

# 5  
Old 07-23-2009
Originally Posted by ryandegreat25
echo 'gLZMQp8i' | sed 's|.|&\n|g'

it worked great, Could you explain the usage of &
I found it
Attempt to match regexp(3,n) against the pattern space. If success-
ful, replace that portion matched with replacement. The
replacement may contain the special character & to refer to that
portion of the pattern space which matched, and the special
escapes \1 through \9 to refer to the corresponding matching
sub-expressions in(1,8) the regexp(3,n).

---------- Post updated at 09:34 PM ---------- Previous update was at 09:28 PM ----------

Originally Posted by radoulov
What you want to do in the loop?
I want to count the totoal number of each class a-z, A-Z and 0-9.

Is there better way than loop?

Last edited by honglus; 07-23-2009 at 10:09 AM..
# 6  
Old 07-23-2009
A possible solution :
$ cat
$ cat
eval $( echo "$*" | \
        awk  '
          { l += gsub(/[a-z]/, "");
            u += gsub(/[A-Z]/, "");
            d += gsub(/[0-9]/, ""); }
          END {
                   l, u, d) } '
echo lower=$lower_cnt
echo upper=$upper_cnt
echo digit=$digit_cnt
$ Happy New Year 2010

# 7  
Old 07-23-2009
I have tried this so...

echo 'gLZMQp8i' | sed 's/\(.\)/\1 /g'

g L Z M Q p 8 i

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