How to loop through every char in a string


 
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# 8  
Old 07-23-2009
I also found the interesting fold command
> echo 'gLZMQp8i' | fold -w1
g
L
Z
M
Q
p
8
i

---------- Post updated at 10:18 PM ---------- Previous update was at 10:12 PM ----------

Quote:
Originally Posted by aigles
A possible solution :
Code:
$ cat count.sh
$ cat c.sh
eval $( echo "$*" | \
        awk  '
          { l += gsub(/[a-z]/, "");
            u += gsub(/[A-Z]/, "");
            d += gsub(/[0-9]/, ""); }
          END {
            printf("lower_cnt=%d;upper_cnt=%d;digit_cnt=%d\n",
                   l, u, d) } '
       )
echo lower=$lower_cnt
echo upper=$upper_cnt
echo digit=$digit_cnt
$ count.sh Happy New Year 2010
lower=9
upper=3
digit=4
$

Jean-Pierre.
Thanks, there must be simple way to do it.
expr is promising, but i can't get it work

Code:
 
expr "gLZMQp8i" : '[0-9]'

Now the quetion is how to sum the the number of each class?
a-z, A-Z and 0-9

---------- Post updated at 10:35 PM ---------- Previous update was at 10:18 PM ----------

That is what i have worked out so far.

var=gLZMQp8i
var2=`echo $var| sed 's/[A-Z]//g'`
total_upper= $((${#var}-${#var2}))
.....
# 9  
Old 07-23-2009
Code:
total_upper=$(echo "$var" | awk '{print gsub(/[A-Z]/,"")}')

Jean-Pierre.
# 10  
Old 07-23-2009
how about something along lines of:

Code:
#   echo 'gLZMQp8i' | fold -w1 | sed 's/[a-z]/%/;s/[A-Z]/^/;s/[0-9]/=/' | sort |uniq -c | sort -nr | tr "^%=" "Ul#"
   4 U
   3 l
   1 #


i.e. 4 upper (U), 3 lower(l) and 1 number (#)

HTH
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