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AWK script for directory listing using GREP

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# 1  
Old 07-21-2009
AWK script for directory listing using GREP
Hi, All -

script1.awk contains the following script:

BEGIN {
printf "The following are directory files:"
"ls -l | grep '^d' | {print $0}"
printf "There were "NR" directories in this list."
}


When I run the script, Here is what I get:

$ awk -f script1.awk
The following are directory files:There were 0 directories in this list. $

When I run "ls -l | grep '^d'" by itself, I get 20 directories. How can I correct this script?
# 2  
Old 07-21-2009
Should be something like:

Code:
BEGIN{
  printf "The following are directories:\n"
  while(("ls -l|grep '^d'"|getline ) > 0) print
}

Regards
# 3  
Old 07-21-2009
Hi, Franklin52 -

HTML Code:
BEGIN {
    printf "The following are directories:\n"
    while(("ls -l|grep '^d'"|getline ) > 0) print
      }
END {
  print "There were "NR" directories in this list."
 }
The directory listing part is working... How do I fix the "NR" line? Right now it is not returing anything.
# 4  
Old 07-21-2009
Try this:

Code:
BEGIN{
  printf "The following are directory files:\n"
  while(("ls -l|grep '^d'"|getline ) > 0){print;i++}
  print "There were "i" directories in this list."
}

# 5  
Old 07-21-2009
I was able to complete my task running the above script. Thank You!
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