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Display the last five dates from the given date

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# 1  
Old 07-10-2009
Display the last five dates from the given date
Hi all,

In Oracle we have got sysdate -1 to find the previous date. Is there any similar way to display date in unix shell scripting?

Kindly help me to display the last five dates from the given date

Thanks,
Geetha
# 2  
Old 07-10-2009
Search datecalc in the forum
https://www.unix.com/unix-dummies-que...n-2-dates.html
# 3  
Old 07-10-2009
Code:
#!/bin/ksh93

for i in {1..5}
do
     printf "%(%D)T\n" "$i day ago"
done

Code:
07/09/09
07/08/09
07/07/09
07/06/09
07/05/09

# 4  
Old 07-10-2009
Here's a little function I created. May not work on all linux systems. Thanks.

Code:
function days_ago {
  DAYAGO=$1
  set -- $(date -d "$DAYAGO days ago" "+%Y %m %d")
  YYYY=$1 ; MM=$2 ; DD=$3
  CHECKDATE=${YYYY}${MM}${DD}
  shift $#
}

# 5  
Old 07-10-2009
Code:
DATE=$(date '+%s')  # now
for I in 0 1 2 3 4; do
  perl -e "print scalar(localtime($DATE)). \"\n\""
  let DATE=$DATE-86400 # 1 day ago
done
 
Fri Jul 10 17:56:11 2009
Thu Jul  9 17:56:11 2009
Wed Jul  8 17:56:11 2009
Tue Jul  7 17:56:11 2009
Mon Jul  6 17:56:11 2009

# 6  
Old 09-20-2009
Hi
Please help on to display the dates if 1st of month is sunday,from sunday(Current month) to thursday of previous month.If its monday ,from monday to thursday of previous month

ex:
1st of month:01-03-2009(Sunday)
28-02-2009
27-02-2009
26-02-2009(thursday)

Thanks,
MR
# 7  
Old 09-21-2009
with GNU date:

application GNUdate GNU date

you can use it to show the date as you expect:

Code:
for i in {1..5}
do
  gdate -d "$i days ago"
done

Last edited by rdcwayx; 09-21-2009 at 04:10 AM..
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