using command line arguments as columns for pattern matching using awk


 
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# 1  
Old 07-08-2009
using command line arguments as columns for pattern matching using awk

Hi,

I wish to use a column, as inputted by a user from command line, for pattern matching.

awk file:

{
if($1 ~ /^8/)
{
print $0> "temp2.csv"
}
}

something like this, but i want '$1' to be any column as selected by the user from command line.

---------------------------
TRIED

{
if($ARGV[2] ~ /^8/)
{
print $0> "temp2.csv"
}
}

AND

{
if("'"$ARGV[2]"'" ~ /^8/)
{
print $0> "temp2.csv"
}
}

Neither works. They work for printing but do not help for pattern matching in 'if'.
# 2  
Old 07-09-2009
Code:
awk '$f ~ /^8/ { print > "temp2.csv }' f=2 myFile

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