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Searching for file and stopping at first item found


 
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# 1  
Old 07-02-2009
Searching for file and stopping at first item found

Hello,

I try to write a shell script that would list all files on a directory and stop when it finds the first item specified on a find or ls command.
How can I tell to the find or ls command to stop when it finds the first ".doc" file for example ?

Thank you
# 2  
Old 07-02-2009
Try...
Code:
for i in *
do
   if [[ `basename $i .doc` != "$i" ]]; then
      exit
   fi
   echo $i
done

# 3  
Old 07-02-2009
Pipe it into head, eg
Code:
find /path -type f -name '*.doc' -print | head -1

# 4  
Old 07-02-2009
Code:
find . -type f -name *.doc 2>/dev/null | sed "q"


Last edited by Scott; 07-02-2009 at 07:10 AM..
# 5  
Old 07-02-2009
thank you rakeshawasthi it works
but how can I make the script goes through subdirectories ?
I've tried this, but all the files comes into the "i" variable, so the script doesnt work :
IFS=
for i in $(find . -type f | awk -F"/" ' { print $2 } ' )
do
if [[ `basename "$i" .chm` != "$i" ]]; then
exit
fi
echo $i
done
# 6  
Old 07-02-2009
Why you are using
Quote:
$(find . -type f | awk -F"/" ' { print $2 } ' )
Isnt this enough...
Code:
find . -type f -print
i.e.
for i in `find . -type f -print`

# 7  
Old 07-02-2009
Code:
ls -lRa /path |awk '/\.doc$/{print;exit}'


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