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Find and replace problem

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# 1  
Old 06-25-2009
Find and replace problem
i have a script that will find a certian pattern and replace it with blank space

Code:
#!/bin/ksh

for i in `cat test.txt | grep "UTILINET" | cut -c 172-191`
do
perl -pi -e 's/$i//g' test.txt
echo "Completed"
done

the command gives some of the below strings
Code:
50032E1B            
50020F8E            
90501D67            
50016FC2            
5000DC3F            
50016E5D            
5002C9C4            
50010DB0            
5002E085

when i m executing the script it is giving error as
./C.sh[3]: no space

Please help me out
# 2  
Old 06-25-2009
Beyond the problem ,the logic behind ur script is not seems to be correct.

If you post you input and the output your expecting , you can expect more results.

Regards
Sastry.P
# 3  
Old 06-25-2009
Is this what you're trying to do?

Code:
awk '/UTILINET/ {print substr($0, 1, 171) substr($0, 192)}' filename

# 4  
Old 06-25-2009
The o/p from the for statement is always one like 50032E1B . So if you decode it in the script it should do the following

for i in 50032E1B
do
perl -pi -e 's/50032E1B//g' test.txt
echo "Completed"
done

Basicall my script is finding the pattren one by one and replacing it with a blankspace
# 5  
Old 06-25-2009
Code:
 
perl -pi -e s/"$i"//g  file_name.txt

worked for me. By the way, no need of "cat" in the for loop, grep "string" file_name is enough.
# 6  
Old 06-25-2009
i have now changed the script to below
Code:
#!/bin/ksh

while read i
do
perl -pi -e 's/'$i'//g' test.txt
echo "Completed"
done < /ednadtu3/u01/pipe/naveed/test/test.txt

But when i do command "cat test.txt | grep "UTILINET" | cut -c 172-191 | head -10" it shows the below strings
Code:
cat test.txt | grep "UTILINET" | cut -c 172-191 | head -10

            |       
            |       
            |       
            |       
            |       
            |       
            |       
            |       
            |       
            |

Why these are coming it should be blankspace na ?
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