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Grep a string and print a string from the line below it

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# 1  
Old 06-23-2009
Grep a string and print a string from the line below it
I know how to grep, copy and paste a string from a line. Now, what i want to do is to find a string and print a string from the line below it. To demonstrate:
Name 1: ABC Age: 3
Sex: Male
Name 2: DEF Age: 4
Sex: Male

Output:
3 Male

I know how to get "3". My biggest problem is to get "Male". The info will ONLY come from the line below where you find "3".

Can anyone help me on this?
# 2  
Old 06-23-2009
where is your code?
# 3  
Old 06-23-2009
Everytime we interact I ask you to show your efforts Smilie
Code:
awk '/Age: 3/{getline;FS=":";print $2}' inputfile

# 4  
Old 06-23-2009
Something like this, perhaps?

Use a multiline regular expression like
Code:
Name \d+: [\w\s]+ Age: (\d+)\nSex: (\w+)\n

then peel off $1 and $2.
# 5  
Old 06-23-2009
Im sorry rake. I only know how to get "3" by grep "Age" |awk '{print $4}' File1
but getting "Male" is my problem.

---------- Post updated 06-24-09 at 12:26 AM ---------- Previous update was 06-23-09 at 07:42 PM ----------
Quote:
Originally Posted by CRGreathouse
Something like this, perhaps?

Use a multiline regular expression like
Code:
Name \d+: [\w\s]+ Age: (\d+)\nSex: (\w+)\n

then peel off $1 and $2.
that is the syntax?
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