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find the last digits of a string

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# 1  
Old 06-22-2009
find the last digits of a string
print out 201 in following string, Please note the chars before 201 are random, no fixed format.


ua07app201
# 2  
Old 06-22-2009
what have you tried?
# 3  
Old 06-22-2009
code removed
Last edited by KevinADC; 06-22-2009 at 03:14 AM.. Reason: agree with ghostdog, lets see some effort
# 4  
Old 06-22-2009
Quote:
Originally Posted by ghostdog74
what have you tried?
Becasue the chars before 201 are random, and it seems sed back reference can only match a fixed pattern, so sed back reference doesn't work for me. I have to end up using perl. But i would like to know the solution in shell.


$ echo ua07app201 | perl -ne ' $_ =~m /(\d+$)/; print $1'

201
# 5  
Old 06-22-2009
try it
echo "ua07app201"|awk -F "" '{print $(NF-2)$(NF-1)$NF}'
# 6  
Old 06-22-2009
Quote:
Originally Posted by pritish.sas
echo "ua07app201"|awk -F "" '{print $(NF-2)$(NF-1)$NF}'
have you tried it?
# 7  
Old 06-22-2009
Code:
# echo ua07app201 | sed 's/.*[^0-9]\(.*\)$/\1/'
201
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