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Awk to print on condition in input file

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# 1  
Old 05-15-2009
Awk to print on condition in input file
I need only those records which has $2 equal to "DEF" independent of case (i.e upper or lower)

Code:
nawk -F"," '$2 ~ /[Dd][Ee][Ff]/{print $0}' file

This returns 3rd record also which i dont want

I tried this but this doesnt work as expected.
Code:
nawk -F"," '$2 == "[Dd][Ee][Ff]"{print $0}' file

Quote:
file:
abc,def
abc,DEf
abc,kDEF
abc,dEF
abc,dEf

i dont need the following record.
abc,kDEF
Help is appreciated.
# 2  
Old 05-15-2009
Code:
nawk -F"," ' tolower($2) == "def" ' file

# 3  
Old 05-15-2009
the easiest thing should be grep, if it's an option for you

Code:
 grep -i ,def file

or

Code:
 grep -i ",def$" file1

just to make sure
# 4  
Old 05-15-2009
Code:
awk -F, '$2 ~ /^[dD][eE][fF]$/'

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